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JEE MATHEMATICS MCQ: COMPLEX NUMBERS

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Analyzing +4 | -1
If 349(x+iy)=(32+i23)100,y∈N3^{49}(x+i y)=\left(\frac{3}{2}+\frac{i}{2} \sqrt{3}\right)^{100}, y \in \mathbf{N}, and x=kyx=k y, then value of kk is
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Correct option: B
±22\pm 2 \sqrt{2}
Option B (±22\pm 2 \sqrt{2}) is correct because by equating the magnitudes and using the given condition x=ky and y being a natural number, we find that k can be ±22\pm 2 \sqrt{2}.

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