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JEE PHYSICS MCQ: OSCILLATIONS

1 Medium

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Application +4 | -1

A particle executes SHM of amplitude

5 \mathrm{~cm}

and period

3 \mathrm{~s}

. The velocity of the particle at a distance

4 \mathrm{~cm}

from the mean position -

View answer and explanation

Correct option: D

6 \mathrm{~cm} / \mathrm{s}

The correct answer is D (

6 \mathrm{~cm} / \mathrm{s}

) because the velocity of a particle in SHM is calculated using the formula

v = \omega \sqrt{a^2 - x^2}

.

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