A cube of side ${\rm{40}}\,\,{\rm{mm}}$ has its upper face displaced by ${\rm{0}}.{\rm{1}}\,{\rm{mm}}$ by a tangential force of ${\rm{8}}\,\,{\rm{kN}}$. The shearing modulus of cube is

$2\,\, \times {10^9}\,{\rm{N}}{{\rm{m}}^{ - 2}}$

$4\,\, \times {10^9}\,{\rm{N}}{{\rm{m}}^{ - 2}}$

$8\,\, \times {10^9}\,{\rm{N}}{{\rm{m}}^{ - 2}}$

$16\,\, \times {10^9}\,{\rm{N}}{{\rm{m}}^{ - 2}}$

NEET UG PHYSICS MCQ: MECHANICAL PROPERTIES OF SOLIDS

1 Easy

1 of 1

Application +4 | -1

A cube of side

\mathrm{40}\,\,\mathrm{mm}

has its upper face displaced by

\mathrm{0}.\mathrm{1}\,\mathrm{mm}

by a tangential force of

\mathrm{8}\,\,\mathrm{kN}

. The shearing modulus of cube is

View answer and explanation

Correct option: A

2\,\, \times {10^9}\,\mathrm{N}{\mathrm{m}^{ - 2}}

Option A (

2 \times {10^9}\,\mathrm{N}{\mathrm{m}^{ - 2}}

) is correct because it is the result of calculating the shearing modulus using the given values of tangential force, area, and displacement.