JEE MATHEMATICS MCQ: TRIGONOMETRY RATIOS

1 Easy

1 of 1

Application +4 | -1

\sin x=-\frac{3}{5}

, where

\pi < x < \frac{3 \pi}{2}

, then

80\left(\tan ^2 x-\cos x\right)

is equal to :

View answer and explanation

Correct option: A

109

Option A (109) is correct because given

\sin x = -\frac{3}{5}

and

\pi < x < \frac{3\pi}{2}

, we can find

\tan x

and

\cos x

, and then evaluate the expression

80(\tan^2 x - \cos x)

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C

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