JEE PHYSICS MCQ: DUAL NATURE OF RADIATION AND MATTER

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Two metallic plates

A

and

B,

each of area

5 \times {10^{ - 4}}{m^2}

are placed parallel to each other at a separation of

1\;cm.

plate

B

carries a positive charge of

33.7\;pc.

A monochromatic beam of light. With photons of energy

5\;eV

each, starts falling on plate

A

t = 0,

so that

{10^{16}}

photons fall on it per square meter per second. Assume that one photoelectron is emitted for energy

{10^{16}}

incident photons. Also assume that all the emitted photoelectrons are collected by plate

B

and the work function of plate

A

remains constant at the value

2\;eV.

Electric field between the plates at the end of 10 seconds is

View answer and explanation

Correct option: A

2 \times {10^3}N/C

Option A (

2 \times {10^3}N/C

) is correct because it is the electric field calculated considering the photoelectrons emitted and collected.

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\lambda=300 \mathrm{~nm}

0.54 \mathrm{~V}

2000\,\mathop \mathrm{A}\limits^ \circ \,

A

B

I

A

B

5000\mathop A\limits^ \circ