JEE PHYSICS MCQ: OSCILLATIONS

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Application +4 | -1

Two simple pendulums of length

0.5 \mathrm{~m}

and

20 \mathrm{~m}

respectively are given small linear displacement in one direction at the same time. They will again be in the phase when the pendulum of shorter length has completed oscillations

\left[n T_1=(n-1) T_2\right.

where

T_1

is time period of shorter length &

T_2

be time period of longer length and

n

are no. of oscillations completed]

View answer and explanation

Correct option: B

Option A (5) is correct because the shorter pendulum completes approximately 5 oscillations when they are again in phase.

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