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JEE MATHEMATICS MCQ: INDEFINITE INTEGRATION

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Application +4 | -1
3a  ∫01  (ax−1a−1)2dx3a\,\,\int \nolimits_0^1 \,\,{\left( {\frac{{ax - 1}}{{a - 1}}} \right)^2}dx is equal to
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Correct option: A
a−1+(a−1)−2a - 1 + {\left( {a - 1} \right)^{ - 2}}
Option A is correct because the integral evaluates to the given expression after simplification, matching the form in option A.

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