JEE MATHEMATICS MCQ: TRIGONOMETRY RATIOS

1 Easy

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Application +4 | -1

The value of

\operatorname{cosec}\left(-1410^{\circ}\right)

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Correct option: B

Option B (2) is correct because

\operatorname{cosec}(-1410^{\circ})

can be simplified using the properties of cosecant function and reference angles.

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\triangle A B C

C

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\sin ^2 \frac{A}{2}+\sin ^2 \frac{B}{2}+\sin ^2 \frac{C}{2}=

\sin ^2(A / 2)+\sin ^2(B / 2)-\sin ^2(C / 2)=