JEE MATHEMATICS MCQ: FUNCTIONS

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Analyzing +4 | -1

For

x \in R, x \neq 0

, let

f_{0}(x)=\frac{1}{1-x}

and

f_{n+1}(x)=f_{0}\left(f_{n}(x)\right)

\mathrm{n}=0,1,2, \ldots

Then the value of

\mathrm{f}_{100}(3)+\mathrm{f}_{1}\left(\frac{2}{3}\right)+\mathrm{f}_{2}\left(\frac{3}{2}\right)

is equal to :

View answer and explanation

Correct option: C

\frac{5}{3}

Option C (5/3) is correct because the function values repeat in a cycle of 3, and substituting the values and simplifying gives 5/3.

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