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JEE MATHEMATICS MCQ: FUNCTIONS

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Application +4 | -1
Let the functionf(x)=x2+x+sin⁡x−cos⁡x+log⁡(1+∣x∣)f\left( x \right) = {x^2} + x + \sin x - \cos x + \log \left( {1 + \left| x \right|} \right) be defined on the interval [0,  1].\left[ {0,\;1} \right]. The odd extension of f(x)f\left( x \right) to the interval [−1,  1]\left[ { - 1,\;1} \right] is
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Correct option: B
−x2+x+sin⁡x+cos⁡x−log⁡(1+∣x∣)- {x^2} + x + \sin x + \cos x - \log \left( {1 + \left| x \right|} \right)
Option B is correct because the odd extension of f(x) involves changing the even terms' signs when x is negative.

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