JEE MATHEMATICS MCQ: PROPERTIES OF TRIANGLES

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Application +4 | -1

Let

A B C

be a triangle such that

\angle A C B=\frac{\pi}{6}

and

a, b

and

c

denote the lengths of the sides opposite to

A, B

and

C

, respectively. The value(s) of

x

for which

a=x^2+x+1, b=x^2-1

and

c=2 x+1

is(are)

View answer and explanation

Correct option: D

4 \sqrt{3}

The provided solution is incorrect. The correct answer should be

1+\sqrt{3}

. By using the cosine rule and simplifying, we find that

x=1+\sqrt{3}

More Questions from PROPERTIES OF TRIANGLES

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{p_1},{p_2},{p_3}

\Delta \;ABC

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\Delta

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k

\Delta \,ABC

a = \left( {b - c} \right)\sec \theta

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\Delta

\Delta \;ABC

\tan A

A

2 s