For the reaction, $2{\rm{N}}{{\rm{O}}_3}\left( {\rm{g}} \right)\leftrightharpoons2{\rm{NO}}\left( {\rm{g}} \right) + {{\rm{O}}_2}\left( {\rm{g}} \right)$ $\left( {{K_c} = 1.8 \times {{10}^{ - 6}}\;{\rm{at }}184^\circ C} \right)$ $(R = 0.00831\;kJ/\left( {mol{\rm{ }}K} \right)$ When ${K_p}\;{\rm{and}}\;{K_c}$ are compared at $184^\circ C$, it is found that

Whether ${K_p}$ is greater than less than or equal to ${K_c}$ depends upon the total gas pressure

NEET UG CHEMISTRY MCQ: Equilibrium

1 Medium

1 of 1

Application +4 | -1

For the reaction,

2\mathrm{N}{\mathrm{O}_3}\left( \mathrm{g} \right)\leftrightharpoons2\mathrm{NO}\left( \mathrm{g} \right) + {\mathrm{O}_2}\left( \mathrm{g} \right)

\left( {{K_c} = 1.8 \times {{10}^{ - 6}}\;\mathrm{at }184^\circ C} \right)

(R = 0.00831\;kJ/\left( {mol\mathrm{ }K} \right)

When

{K_p}\;\mathrm{and}\;{K_c}

are compared at

184^\circ C

, it is found that

View answer and explanation

Correct option: D

{K_p}

is greater than

{K_c}

Option D (

{K_p}

is greater than

{K_c}

) is correct because for this reaction, the change in the number of moles of gas is positive, leading to

{K_p} > {K_c}

Practice All Chapter MCQs →

Mg{(HC{O_3})_2}

MgC{O_3}

Mg{(OH)_2}

MgC{O_3}

K_{\mathrm{P}}

\mathrm{CaCO}_3

4.5 \times 10^{-2}

\mathrm{C}(\mathrm{s})+\mathrm{CO}_2(\mathrm{g}) \rightleftharpoons 2 \mathrm{CO}(\mathrm{g}),

K_{\mathrm{P}}

2.0 \mathrm{~atm}.

\mathrm{CaO}

\mathrm{CaCO}_3

+

\leftrightharpoons

\mathrm{PC}{\mathrm{l}_5}\leftrightharpoons\mathrm{PC}{\mathrm{l}_3} + \mathrm{C}{\mathrm{l}_2}

{K_{\mathrm{eq}}} = 0.41

\mathrm{p}{K_a}