JEE MATHEMATICS MCQ: COMPLEX NUMBERS

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Application +4 | -1

\omega=\cos \frac{\pi}{n}+i \sin \frac{\pi}{n}

, then value of

1+\omega+\omega^2+\ldots+\omega^{n-1}

View answer and explanation

Correct option: C

1+i \cot (\pi / 2 n)

The correct answer is D (

\pi / 2

) because the odd functions integrate to zero over the symmetric interval, leaving only the integral of the constant function 1.

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