JEE MATHEMATICS MCQ: TANGENTS & NORMALS

1 Easy

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Application +4 | -1

The abscissa of the points, where the tangent to curve

y = {x^3} - 3{x^2} - 9x + 5

is parallel to

x

-axis , are

View answer and explanation

Correct option: D

x = - 1\;and\;3

Option D (

x = - 1\;and\;3

) is correct because these are the x-coordinates where the derivative of the curve is zero, indicating a horizontal tangent.

More Questions from TANGENTS & NORMALS

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a

y=x^3-a x

x^2 y=1-y

x y=1-y

C

y^3-3 x y+2=0

H

\mathrm{C}

x

V

C

y

y-e^{x y}+x=0

y = f\left( x \right)

x

x = a\left( {\theta - \sin \theta } \right),\;y = a\left( {1 + \cos \theta } \right)

\theta = \left( {2k + 1} \right)\pi ,\;k \in Z