JEE MATHEMATICS MCQ: INDEFINITE INTEGRATION

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Application +4 | -1

\int e^{-2 x} \sin 3 x d x=

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Correct option: D

-\frac{1}{13} e^{-2 x}[2 \sin 3 x+3 \cos 3 x]+c

Option D (

-\frac{{1}}{{13}} e^{-2 x}[2 \sin 3 x+3 \cos 3 x]+c

) is correct because it is the result of integrating the given expression using integration by parts twice.

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