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NEET UG CHEMISTRY MCQ: SOLUTIONS

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{K}_{{H}}

value for some gases at the same temperature '

{T}

' are given:

\begin{array}{cccccccccccccccccccc} {{\text{Gas}}}&{{K_H}/k\,\,{\text{bar}}} \\ {Ar}&{40.3} \\ {C{O_2}}&{1.67} \\ {HCHO}&{1.83 \times {{10}^{ - 5}}} \\ {C{H_4}}&{0.413} \end{array}

where

{K}_{{H}}

is Henry's Law constant in water. The order of their solubility in water is:

View answer and explanation

Correct option: B

{Ar} < {CO}_2 < {CH}_4 < {HCHO}

Option B (

{Ar} < {CO}_2 < {CH}_4 < {HCHO}

) is correct because the solubility of a gas is inversely proportional to its Henry's Law constant (

K_H

).

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