JEE MATHEMATICS MCQ: COMPLEX NUMBERS

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Application +4 | -1

z

is any complex number such that

z+\frac{1}{z}=1

, then the value of

z^{99}+\frac{1}{z^{99}}

View answer and explanation

Correct option: D

-2

Option B (-2) is correct because the given condition implies that z is a complex cube root of unity (specifically

-\omega

-\omega^2

), and substituting this into the expression yields -2.

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