JEE PHYSICS MCQ: OSCILLATIONS

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x=5 \sin \left(\pi t+\frac{\pi}{3}\right) \mathrm{m}

represents the motion of a particle executing simple harmonic motion, the amplitude and time period of motion, respectively, are

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Correct option: A

5 \mathrm{~m}, 2 \mathrm{~s}

Option A (5 m, 2 s) is correct because the amplitude is directly read from the equation, and the time period is calculated from the angular frequency.

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