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JEE PHYSICS MCQ: GRAVITATION

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Application +4 | -1
A body is projected upwards with a velocity of 3×11.2 km s−13 \times 11.2 \mathrm{~km} \mathrm{~s}^{-1} from the surface of earth. What will be the velocity of the body when it escapes from the gravitational pull of earth?
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Correct option: D
8×11.2 kms−1\sqrt{8} \times 11.2 \mathrm{~kms}^{-1}
Option D (8×11.2 kms−1\sqrt{8} \times 11.2 \mathrm{~kms}^{-1}) is correct because it calculates the final velocity after escaping Earth's gravity using energy conservation.

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