When 1 faraday of electricity is passed through ${\rm{CuS}}{{\rm{O}}_4}$ solution, number of atoms formed is :

NEET UG CHEMISTRY MCQ: ELECTRO CHEMISTRY

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When 1 faraday of electricity is passed through

\mathrm{CuS}{\mathrm{O}_4}

solution, number of atoms formed is :

View answer and explanation

Correct option: B

3.01 \times {10^{23}}

Option B (

3.01 \times {10^{23}}

) is correct because 1 Faraday deposits 0.5 moles of Cu atoms, which is

3.01 \times {10^{23}}

atoms.

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A{l^{3 + }}

{H_2}

{H^ + }

\mathrm{LiCl},{\rm{NaCl {\kern 1pt}{\kern 1pt}and {\kern 1pt}{\kern 1pt}KCl}}

\left(\mathrm{CuSO}_4\right)

\mathrm{A}{\mathrm{l}^{3 + }}