JEE MATHEMATICS MCQ: FUNCTIONS

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Analyzing +4 | -1

The domain of the function

f(x)=\log _2\left(-\log _{1 / 2}\left(1+\frac{1}{\sqrt[4]{x}}\right)-1\right)

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Correct option: A

0 < x < 1

Option A (No solution) is correct because g(x) is always negative, thus it can never be equal to zero.

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S=\left\{x: f(x)=f^{-1}(x)\right\}