JEE PHYSICS MCQ: THERMAL PROPERTIES OF MATTER

1 Medium

1 of 1

Application +4 | -1

Compare the rate of loss of heat from a metal sphere of temperature

827^{\circ} \mathrm{C}

, with the rate of loss of heat from the same sphere at

427^{\circ} \mathrm{C}

, if the temperature of surroundings is

27^{\circ} \mathrm{C}

View answer and explanation

Correct option: A

6.276: 1

Option A (

6.276: 1

) is correct because it is calculated using the Stefan-Boltzmann law of radiation.

More Questions from THERMAL PROPERTIES OF MATTER

Practice All Chapter MCQs →

n = \frac{{PV}}{{RT}},n =

{25^0}

{0^0}C

E\,\,W{m^{ - 2}}

\left( {\frac{T}{2}} \right)K