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JEE MATHEMATICS MCQ: PROPERTIES OF TRIANGLES

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In a △ABC,2s=\triangle A B C, 2 s= perimeter and R=R= circumradius. Then, SR\frac{S}{R} is equal to
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Correct option: A
sin⁡A+sin⁡B+sin⁡C\sin A+\sin B+\sin C
Option A (sin⁡A+sin⁡B+sin⁡C\sin A + \sin B + \sin C) is correct because using the sine rule, s/Rs/R can be expressed as the sum of sines of the angles.

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