Question

During complete combustion of one mole of butane, $2658 \mathrm{~kJ}$ of heat is released. The thermochemical reaction for above change is

Accepted Answer

$\mathrm{C}_4 \mathrm{H_{10}(g})+\frac{13}{2} \mathrm{O_2(g}) \rightarrow 4 \mathrm{CO_2(g})+ 5 \mathrm{H}_2 \mathrm{O}(l) ; \Delta_C H =-2658.0 \mathrm{~kJ} \mathrm{~mol}^{-1}$

Answer

$2 \mathrm{C}_4 \mathrm{H}_{10}(\mathrm{g})+13 \mathrm{O}_2(\mathrm{g}) \rightarrow 8 \mathrm{CO}_2(\mathrm{g})+10 \mathrm{H}_2 \mathrm{O}(l); \Delta_C H=-2658.0 \mathrm{~kJ} \mathrm{~mol}^{-1}$

Answer

$\mathrm{C}_4 \mathrm{H_{10}(g})+\frac{13}{2} \mathrm{O_2(g}) \rightarrow 4 \mathrm{CO_2(g})+ 5 \mathrm{H}_2 \mathrm{O}(l) ; \Delta_C H =-1329.0 \mathrm{~kJ} \mathrm{~mol}^{-1}$

Answer

$\mathrm{C}_4 \mathrm{H_{10}(g})+\frac{13}{2} \mathrm{O_2(g}) \rightarrow 4 \mathrm{CO_2(g})+ 5 \mathrm{H}_2 \mathrm{O}(l) ; \Delta_C H =+2658.0 \mathrm{~kJ} \mathrm{~mol}^{-1}$

NEET UG CHEMISTRY MCQ: THERMODYNAMICS

More Questions from THERMODYNAMICS