JEE MATHEMATICS MCQ: FUNCTIONS

1 Medium

1 of 1

Analyzing +4 | -1

If the function

f(x)=2 \tan x+(2 a+1) \ln |\sec x|+(a-2) x

is increasing in

\left(0, \frac{\pi}{2}\right)

then range of '

a

' equal to

View answer and explanation

Correct option: D

[0, \infty)

Option D ([0, ∞)) is correct because for f(x) to be increasing, its derivative must be greater than or equal to 0, which leads to the condition a ≥ 0.

More Questions from FUNCTIONS

Practice All Chapter MCQs →

f:(-\infty, 2] \longrightarrow(-\infty, 4]

, where

f(x)=x(4-x)

, then

f^{-1}(x)

is given by: If

g(f(x))=|\sin x|

and

f(g(x))=(\sin \sqrt{x})^2

, then Let

f:\left( {2,\;3} \right) \to \left( {0,\;1} \right)

be defined by

f\left( x \right) = x - \left[ x \right]

, then

{f^{ - 1}}\left( x \right)

equals Let

f: R \rightarrow R

be defined as

f(x)=x^4

, Choose the correct answer. Which of the following functions are odd functions Let

f(x)=(x+1)^2-1(x \geq-1)

. Then the set

S=\left\{x: f(x)=f^{-1}(x)\right\}

contains