The osmotic pressure $(At\;27^\circ C)$ of an aqueous solution (200 mL) containing 6 g of a protein is $2 \times {10^{ - 3}}\;{\rm{atm}}.$ If $R = 0.080{\rm{ }}L - atm{\rm{ }}\;mo{l^{ - 1}}{K^{ - 1}},$ the molecular weight of protein is

NEET UG CHEMISTRY MCQ: SOLUTIONS

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The osmotic pressure

(At\;27^\circ C)

of an aqueous solution (200 mL) containing 6 g of a protein is

2 \times {10^{ - 3}}\;\mathrm{atm}.

R = 0.080\mathrm{ }L - atm\mathrm{ }\;mo{l^{ - 1}}{K^{ - 1}},

the molecular weight of protein is

View answer and explanation

Correct option: B

3.6 \times {10^5}

Option B (

3.6 \times {10^5}

) is correct because it is the calculated molecular weight of the protein using the osmotic pressure formula.

Practice All Chapter MCQs →

0.52\,K\,kg\,mo{l^{ - 1}}

A

B

B

A

B

--{0.93^0}C

{K_f}

1.86\mathrm{ }K\mathrm{ }kg\mathrm{ }mo{l^{ - 1}}