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NEET UG CHEMISTRY MCQ: SOLUTIONS

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Analyzing +4 | -1
A solute when distributed between two immiscible phases remains associated in phase II and dissociated in phase I. If αis the degree of dissociation and n is the number of molecules associated then :
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Correct option: D
K=cI(1−α)cIInK = \frac{{{c_\mathrm{I}}\left( {1 - \mathrm{\alpha }} \right)}}{{\sqrt[n]{{{c_{\mathrm{II}}}}}}}
Option D is correct because it represents the distribution law when the solute associates in phase II and dissociates in phase I, considering the degree of dissociation and association number.

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