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JEE MATHEMATICS MCQ: DIFFERENTIAL EQUATIONS

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Application +4 | -1
dydx=yx+2d(yx)ϕ(yx)\frac{d y}{d x}=\frac{y}{x}+2 \frac{d\left(\frac{y}{x}\right)}{\phi\left(\frac{y}{x}\right)} has the solution .......
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Correct option: C
ϕ(yx)=kx2\phi\left(\frac{y}{x}\right)=k x^2
Option C (ϕ(yx)=kx2\phi(\frac{{y}}{{x}}) = kx^2) is correct because it is the solution obtained by substituting u=yxu = \frac{{y}}{{x}} and integrating the resulting separable equation.

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