JEE PHYSICS MCQ: SYSTEM OF PARTICLES

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A body A of mass M while falling vertically downwards under gravity breaks into two parts; a body B of mass

\frac{1}{3}M

and a body C of mass

\frac{2}{3}M

. The centre of mass of bodies B and C taken together shifts compared to that of body A towards

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Correct option: B

Does not shift

Option B (Does not shift) is correct because the acceleration of the center of mass remains the same (g) after the break, so there's no shift.

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\mathrm{AB}

\mathrm{L}

\mu(x)=a+\frac{b x}{L}

x

\mathrm{A}

\mathrm{CM}

\left(\frac{7}{12}\right) \mathrm{L}

\mathrm{A}

\mathrm{b}

1.0 \mathrm{~g}

8 \mathrm{~cm}

\omega = {t^4} + 2{t^3}

t = 1\,sec

\left( {rad\,{s^{ - 2}}} \right)