JEE PHYSICS MCQ: THERMAL PROPERTIES OF MATTER

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An amount of water of mass 20 g at

{0^0}C

is mixed with 40 g of water

{10^0}C

final temperature of the mixture

View answer and explanation

Correct option: D

{6.66^0}C

Option D (

{6.66^0}C

) is correct because it represents the final temperature calculated using the principle of heat exchange between the two water masses.

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n = \frac{{PV}}{{RT}},n =

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{0^0}C

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\left( {\frac{T}{2}} \right)K