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JEE MATHEMATICS MCQ: PROPERTIES OF TRIANGLES

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If in a Δ  ABC,1a+c+1b+c=3a+b+c\Delta \;ABC,\frac{1}{{a + c}} + \frac{1}{{b + c}} = \frac{3}{{a + b + c}}, then the value of the angle CC is
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Correct option: A
60∘60^\circ
Option A (60∘60^\circ) is correct because the given equation leads to cos⁡C=12\cos C = \frac{1}{2}, which implies C=60∘C = 60^\circ.

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