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JEE MATHEMATICS MCQ: FUNCTIONS

1 Easy

1 of 1

Application +4 | -1

If

f(x) \Rightarrow \cos x \mid

and

g(x)=[x]

, then

g

of

(x)

is equal to

View answer and explanation

Correct option: C

[|\cos x|]

Option C (

[|\cos x|]

) is correct because

g(f(x)) = g(|\cos x|) = [|\cos x|]

.

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f:(-\infty, 2] \longrightarrow(-\infty, 4]

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g(f(x))=|\sin x|

f(g(x))=(\sin \sqrt{x})^2

f:\left( {2,\;3} \right) \to \left( {0,\;1} \right)

f\left( x \right) = x - \left[ x \right]

{f^{ - 1}}\left( x \right)

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f(x)=x^4

, Choose the correct answer. Which of the following functions are odd functions Let

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S=\left\{x: f(x)=f^{-1}(x)\right\}