Skip to main content
Back to GRAVITATION

JEE PHYSICS MCQ: GRAVITATION

1 Medium
1 of 1
Application +4 | -1
A satellite of mass 1000 kg1000 \mathrm{~kg} is supposed to orbit the earth at a height of 2000 km2000 \mathrm{~km} above the earth's surface. Find (a) its speed in the orbit, (b) its kinetic energy, (c) the potential energy of the earth-satellite system and (d) its time period. Mass of the earth =6×1024 kg=6 \times 10^{24} \mathrm{~kg}.
View answer and explanation
Correct option: A
6.9 km/s; 2.38×1010 J;−4.76×1010 J; 2.1 hour6.9 \mathrm{~km/s};\,2.38 \times 10^{10} \mathrm{~J};-4.76 \times 10^{10} \mathrm{~J};\,2.1\text{ hour}
The correct answer is A (6.9 km/s; 2.38×1010 J;−4.76×1010 J; 2.1 hour6.9 \mathrm{~km/s};\,2.38 \times 10^{10} \mathrm{~J};-4.76 \times 10^{10} \mathrm{~J};\,2.1\text{ hour}) because it correctly calculates the speed, kinetic energy, potential energy, and time period of the satellite.

More Questions from GRAVITATION

Practice All Chapter MCQs →
Type at least 2 characters or jump directly:
🔓

Save your learning progress

Sign in with a free account to save your practice answers and quiz results, then return to them when you revise.