NEET UG CHEMISTRY MCQ: ELECTRO CHEMISTRY

1 Easy

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Understanding +4 | -1

The correct value of e.m.f. of cell is given by :

i)

{E_{cell}} = {E_{OP}}{\kern 1pt} anode - {E_{RP}}{\kern 1pt} cathode

ii)

{E_{cell}} = {E_{OP}}{\kern 1pt} anode + {E_{RP}}{\kern 1pt} cathode

iii)

{E_{cell}} = {E_{RP}}{\kern 1pt} anode + {E_{RP}}{\kern 1pt} cathode

iv)

{E_{cell}} = {E_{OP}}{\kern 1pt} anode - {E_{OP}}{\kern 1pt} cathode

View answer and explanation

Correct option: D

(ii) and (iv)

Option D ((ii) and (iv)) is correct because

{E_{cell}} = {E_{OP}}{\kern 1pt} anode + {E_{RP}}{\kern 1pt} cathode

and

{E_{cell}} = {E_{OP}}{\kern 1pt} anode - {E_{OP}}{\kern 1pt} cathode

are both valid ways to calculate cell potential.

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