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JEE MATHEMATICS MCQ: FUNCTIONS

1 Easy

1 of 1

Application +4 | -1

If

g(x)=x^2+x-2

and

\frac{1}{2} g \circ f(x)=2 x^2-5 x+2

, then

f(x)

is

View answer and explanation

Correct option: A

2 x-3

Option A (

2x - 3

) is correct because solving for

f(x)

in the equation

\frac{1}{2}g(f(x)) = 2x^2 - 5x + 2

yields

f(x) = 2x - 3

.

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S=\left\{x: f(x)=f^{-1}(x)\right\}