JEE MATHEMATICS MCQ: FUNCTIONS

1 Medium

1 of 1

Application +4 | -1

f\left( x \right) = \frac{{2x - 1}}{{x + 5}}\left( {x \ne - 5} \right)

, then

{f^{ - 1}}\left( x \right)

is equal to

View answer and explanation

Correct option: B

\frac{{5x + 1}}{{2 - x}},\;x \ne 2

Option B (

\frac{{5x + 1}}{{2 - x}},\;x \ne 2

) is correct because it represents the inverse function obtained by swapping x and y and solving for y.

More Questions from FUNCTIONS

Practice All Chapter MCQs →

f:(-\infty, 2] \longrightarrow(-\infty, 4]

f(x)=x(4-x)

f^{-1}(x)

g(f(x))=|\sin x|

f(g(x))=(\sin \sqrt{x})^2

f:\left( {2,\;3} \right) \to \left( {0,\;1} \right)

f\left( x \right) = x - \left[ x \right]

{f^{ - 1}}\left( x \right)

f: R \rightarrow R

f(x)=x^4

f(x)=(x+1)^2-1(x \geq-1)

S=\left\{x: f(x)=f^{-1}(x)\right\}