JEE MATHEMATICS MCQ: INDEFINITE INTEGRATION

1 Easy

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Application +4 | -1

The integral

\int e^{\tan ^{-1} x}\left(\frac{1+x+x^2}{1+x^2}\right) \mathrm{d} x

is equal to

View answer and explanation

Correct option: C

x e^{\tan ^{-1} x}+C

Option C (

x e^{\tan ^{-1} x}+C

) is correct because the integral can be solved using substitution and the formula

\int e^x(f(x)+f'(x)) dx = e^x f(x) + C

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