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JEE MATHEMATICS MCQ: COMPLEX NUMBERS

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Application +4 | -1

If

(\cos \theta+i \sin \theta)(\cos 2 \theta+i \sin 2 \theta) \ldots(\cos n \theta+i \sin n \theta)=1

, then

\theta=

View answer and explanation

Correct option: C

\frac{4 k \pi}{n(n+1)}, k \in Z

Option C (

\frac{{4 k \pi}}{{n(n+1)}}, k \in Z

) is correct because it is derived by equating the sum of angles to

2k\pi

and solving for

\theta

.

More Questions from COMPLEX NUMBERS

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The number of non-zero integer solutions of the equation

{\left| {1 - i} \right|^x} = {2^x}

|z|=1

z \neq \pm 1

, then for any complex number

z, \frac{z}{1-z^2}

\left|z_r-r\right| \leq r, \forall r=1,2,3, \ldots, n

\left|\sum\limits_{r=1}^n z_r\right|

is less than The roots of the cubic equation

(z+a b)^3=a^3

a \neq 0

represents the vertices of a triangle. If

\alpha, \beta

\gamma

are the roots, then find the value of

|\alpha-\beta|

. Number of solutions of the equation

{z^2} + {\left| z \right|^2} = 0,

z \in C

2x = - 1 + \sqrt 3 i

, then the value of

{\left( {1 - {x^2} + x} \right)^6} - {\left( {1 - x + {x^2}} \right)^6}