$\frac{{3 + 2i\sin {\rm{\theta }}}}{{1 - 2i\sin {\rm{\theta }}}}\;$ will be real, if $\theta $ is

JEE MATHEMATICS MCQ: COMPLEX NUMBERS

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\frac{{3 + 2i\sin \mathrm{\theta }}}{{1 - 2i\sin \mathrm{\theta }}}\;

will be real, if

\theta

View answer and explanation

Correct option: C

n\pi

Option C (

n\pi

) is correct because for the given expression to be real, the imaginary part must be zero, which occurs when

\sin \theta = 0

, implying

\theta = n\pi

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