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NEET • PHYSICS • WAVES

Waves practice · Mixed difficulty

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121 Medium
121 of 215
Analyzing +4 | -1
The displacement yy of a particle on a straight line is given by y=f(x,t)y=f(x, t), as a function of time. Which of the following functions does not represent wave motion?
View answer and explanation
Correct option: C
y=Asin⁡(k2x2−ω2t2)y=A \sin \left(k^2 x^2-\omega^2 t^2\right)
Option D (The velocity of wave propagation is 2 cm/s2 \mathrm{~cm} / \mathrm{s}) is correct because the calculated velocity from the given wave equation is 5000 cm/s5000 \mathrm{~cm} / \mathrm{s}, not 2 cm/s2 \mathrm{~cm} / \mathrm{s}.
122 Easy
122 of 215
Understanding +4 | -1
To decrease the fundamental frequency of a stretched string fixed at both ends. Which of the following option is correct?
View answer and explanation
Correct option: C
Increase its length
Option C (Increase its length) is correct because the fundamental frequency of a stretched string is inversely proportional to its length, as described by the formula f=12LTμf = \frac{1}{2L}\sqrt{{\frac{T}{\mu}}}.
123 Easy
123 of 215
Remembering +4 | -1
‘SONAR’ emits which of the following waves
View answer and explanation
Correct option: B
Ultrasonic waves
Option B (Ultrasonic waves) is correct because SONAR (Sound Navigation and Ranging) uses ultrasonic waves to detect objects underwater.
124 Easy
124 of 215
Application +4 | -1
A resonance tube of (closed organ pipe) air column of length 20 cm resonates with a tuning fork of frequency 250 Hz. The speed of sound in air is [in ms−1]m{s^{ - 1}}]
View answer and explanation
Correct option: B
200
Option B (200) is correct because the speed of sound can be calculated using the formula v = 4fL for a closed organ pipe at resonance.
125 Medium
125 of 215
Application +4 | -1
A cylindrical tube, closed at one end, has a fundamental frequency f in air. The 14th\frac{1}{4}th of the tube is filled with water. The fundamental frequency of the air column is now
View answer and explanation
Correct option: B
4f3\frac{{4f}}{3}
Option B (4f3\frac{{4f}}{3}) is correct because filling 1/4 of the tube with water reduces the effective length of the air column, increasing the fundamental frequency.
126 Medium
126 of 215
Application +4 | -1
The instantaneous displacement of a simple harmonic oscillator is given by =a   cos⁡[ωt+π4]= a\,\,\,\cos \left[ {\omega t + \frac{\pi }{4}} \right]. Its speed will be maximum at the time
View answer and explanation
Correct option: D
π4ω\frac{\pi }{{4\omega }}
Option D (π4ω\frac{\pi }{{4\omega }}) is correct because the speed is maximum when the displacement is zero, which occurs at t=π4ωt = \frac{\pi }{{4\omega }} for the given equation.
127 Medium
127 of 215
Application +4 | -1
The equation of a simple harmonic wave is given by y=3sin⁡π2(50t−x)y = 3\sin \frac{\pi }{2}\left( {50t - x} \right) Where x and y are in metres and t is in seconds. The ratio of maximum particle velocity to the wave velocity is
View answer and explanation
Correct option: D
32π\frac{3}{2}\pi
Option D (32π\frac{3}{2}\pi) is correct because the ratio of maximum particle velocity to wave velocity is calculated using the given wave equation.
128 Medium
128 of 215
Analyzing +4 | -1
The displacement of particles in a string stretched in the xx direction is represented by yy. Among the following expressions for yy, those describing wave motion are :
View answer and explanation
Correct option: A
cos⁡kxsin⁡ωt\cos k x \sin \omega t
Option A (cos⁡kxsin⁡ωt\cos k x \sin \omega t) is correct because it represents a valid solution to the wave equation.
129 Medium
129 of 215
Remembering +4 | -1
A travelling wave reflected at an open boundary undergoes a phase change of
View answer and explanation
Correct option: B
0
Option B (0) is correct because a wave reflected at an open boundary undergoes no phase change.
130 Medium
130 of 215
Application +4 | -1
If two coherent waves are represented by y1=4sin⁡ωt{y_1} = 4\sin \omega t and y2=3sin⁡(ωt+π/3){y_2} = 3\sin \left( {\omega t + \pi /3} \right) interfere at a point, the amplitude of resulting wave will be about
View answer and explanation
Correct option: B
6.1
Option B (6.1) is correct because it is the approximate amplitude calculated using the superposition principle for coherent waves.
131 Easy
131 of 215
Understanding +4 | -1
A plane progressive wave is given by y=2cos⁡2π(330t−x)m.y=2 \cos 2 \pi(330 t-x)m. The frequency of the wave is:
View answer and explanation
Correct option: B
330 Hz330 \mathrm{~Hz}
Option B is correct because the frequency can be extracted from the coefficient of t in the wave equation.
132 Medium
132 of 215
Analyzing +4 | -1
Assertion(A): Speed of sound in O2\mathrm{O}_2 gas at temperature TT is vv. If temperature is increased to 2T2 T, the molecular oxygen breaks into atomic oxygen. Then, speed of sound under these conditions will become 2v2 v.

Reason(R): With increase in humidity in air, speed of sound increases.
View answer and explanation
Correct option: B
If both Assertion and Reason are correct but Reason is not the correct explanation of Assertion.
Option B (If both Assertion and Reason are correct but Reason is not the correct explanation of Assertion) is correct because both the assertion and the reason are true statements, but the reason does not explain the assertion.
133 Easy
133 of 215
Application +4 | -1
A string of length 1 m1 \mathrm{~m} and mass 5 g5 \mathrm{~g} is fixed at both ends. The tension in the string is 8.0 N8.0 \mathrm{~N}. The string is set into vibration using an external vibrator of frequency 100 Hz100 \mathrm{~Hz}. The separation between successive nodes on the string in cm\mathrm{cm} is close to
View answer and explanation
Correct option: A
20
Option A (20) is correct because the separation between successive nodes is half the wavelength, and the wavelength can be calculated from the given frequency and wave speed.
134 Medium
134 of 215
Analyzing +4 | -1
Two tuning fork, AA and BB produce notes of frequencies 258  Hz258\,\,Hz and 262  Hz262\,\,Hz. An unknown note sounded with a produces certain beats. When the same note is sounded with BB, the beat frequency gets doubled, the unknown frequency is
View answer and explanation
Correct option: B
254 Hz254\mathrm{ }\,Hz
Option B (254 Hz254\mathrm{ }\,Hz) is correct because the beat frequency with A is 4 Hz, and with B it's 8 Hz, satisfying the condition that the beat frequency with B is doubled.
135 Medium
135 of 215
Analyzing +4 | -1
A tuning fork AA of frequency 512 Hz produce 5 beats/sec. When sounded with another tuning fork BB of unknown frequency. If BB is loaded with wax the numbers of beats is again 5 beats/second. The frequency of tuning fork BB before it was loaded is:
View answer and explanation
Correct option: C
517 Hz
Option C (517 Hz) is correct because adding wax to tuning fork B decreases its frequency, and since the number of beats remained the same, the original frequency must have been higher than 512 Hz.
136 Hard
136 of 215
Application +4 | -1
A travelling wave is produced on a long horizontal string by vibrating an end up and down sinusoidally. The amplitude of vibration is 1.0 cm1.0 \mathrm{~cm} and the displacement becomes zero 200 times per second. The linear mass density of the string is 0.10 kg m−10.10 \mathrm{~kg} \mathrm{~m}^{-1} and it is kept under a tension of 90 N. Find the velocity and acceleration of the particle at x=50 cmx=50 \mathrm{~cm} at time t=10 mst=10 \mathrm{~ms}.
View answer and explanation
Correct option: A
5.4 m/s; 2 km/s25.4 \mathrm{~m/s};\,2 \mathrm{~km/s}^2
Option A (5.4 m/s; 2 km/s25.4 \mathrm{~m/s};\,2 \mathrm{~km/s}^2) is correct because it calculates the velocity and acceleration of the particle at the given position and time using the wave equation.
137 Easy
137 of 215
Application +4 | -1
The speed sound in air is 332 m/s. The speed of sound in air in units of km per hour will be
View answer and explanation
Correct option: D
1195.2 km/h
Option D is correct because it correctly converts meters per second to kilometers per hour.
138 Medium
138 of 215
Understanding +4 | -1
Speed of sound at constant temperature depends on
View answer and explanation
Correct option: D
None of the above
Option D (None of the above) is correct because the speed of sound at a constant temperature depends on the properties of the gas, but not directly on pressure or density individually. It depends on the ratio of pressure and density.
139 Medium
139 of 215
Analyzing +4 | -1
The wave function of a pulse is given by y=3(2x+3t)2y=\frac{3}{(2 x+3 t)^2} where xx and yy are in metre and tt is in second.

i) Identify the direction of propagation.

ii) Determine the wave velocity of the pulse.
View answer and explanation
Correct option: A
−1.5 m/s-1.5 \mathrm{~m} / \mathrm{s}
Option A (-1.5 m/s) is correct because the wave is propagating in the negative x-direction and the velocity is determined by the ratio of the coefficients of t and x.
140 Easy
140 of 215
Analyzing +4 | -1
If fundamental frequency is 50 and next successive frequencies are 150 and 250 then it is
View answer and explanation
Correct option: B
A pipe closed at one end
Option B (A pipe closed at one end) is correct because the frequencies are odd multiples of the fundamental frequency.
141 Medium
141 of 215
Analyzing +4 | -1
The phase difference between the two given waves is y1=a1sin⁡(ωt−2πλX)   y2=a2cos⁡(ωt−2πλX+ϕ) {y_1} = {a_1}\sin \left( {\omega t - \frac{{2\pi }}{\lambda }X} \right)\,\,\,{y_2} = {a_2}\cos \left( {\omega t - \frac{{2\pi }}{\lambda }X + \phi } \right)\,
View answer and explanation
Correct option: C
π2+(ϕ)\frac{\pi }{2} + \left( \phi \right)
Option C (π2+(ϕ)\frac{\pi }{2} + \left( \phi \right)) is correct because the phase difference accounts for the cosine function and the additional phase angle ϕ\phi.
142 Medium
142 of 215
Analyzing +4 | -1
A source of sound gives 55 beats s−1{\mathrm{s}^{ - 1}} when sounded with another source of frequency 100  Hz100\,\,Hz. The second harmonic of the source together with a source of frequency 205  Hz205\,\,Hz gives 5  beats  s(−1)5\,\,beats\,\,{s^{( - 1)}}. What is the frequency of the source?
View answer and explanation
Correct option: A
105Hz105\mathrm{ }Hz
Option A (105Hz105\mathrm{ }Hz) is correct because it satisfies both beat frequency conditions: 5 Hz with 100 Hz and 5 Hz with 205 Hz for the second harmonic.
143 Medium
143 of 215
Analyzing +4 | -1
Assertion: For same length but different gas COP fundamental frequency are different.
Reason: Here frequency is proportional to velocity for same length given.
View answer and explanation
Correct option: A
If both Assertion & reason are True & the Reason is a correct explanation of the Assertion
Option A is correct because the fundamental frequency depends on the velocity of sound in the gas, which is different for different gases, and the frequency is directly proportional to the velocity for a given length.
144 Medium
144 of 215
Application +4 | -1
On the superposition of two harmonic oscillations represented by X1=asin⁡(ωt+ϕ1){X_1} = a\sin \left( {\omega t + {\phi _1}} \right) and X2=asin⁡(ωt+ϕ2){X_2} = a\sin \left( {\omega t + {\phi _2}} \right)a resulting oscillation with the same time period and same amplitude is obtained. The value of ϕ1−ϕ2{\phi _1} - {\phi _2} is
View answer and explanation
Correct option: A
120 ∘C120\,^\circ C
Option A (120 ∘C120\,^\circ C) is correct because when two oscillations of the same amplitude result in an oscillation of the same amplitude, the phase difference must be 120 degrees.
145 Medium
145 of 215
Application +4 | -1
Two sound waves with wavelength 5m and 6m respectively, each propagate in the gas with velocity 330 m/s. We except the following number of beats per second
View answer and explanation
Correct option: D
11
Option D (11) is correct because the beat frequency is the absolute difference between the frequencies of the two waves.
146 Medium
146 of 215
Application +4 | -1
A transverse wave of amplitude 0.5  m0.5\,\,m and wavelength 1m1m and frequency 2  Hz2\,\,Hz is propagating in a string in the negative xx-direction. The expression for this wave is
View answer and explanation
Correct option: B
y(x,t)=0.5  cos⁡(2πx+4πt)y\left( {x,t} \right) = 0.5\,\,\cos \left( {2\pi x + 4\pi t} \right)
Option B (y(x,t)=0.5 cos⁡(2πx+4πt)y(x,t) = 0.5\,\cos (2\pi x + 4\pi t)) is correct because it represents a wave with the given amplitude, wavelength, and frequency propagating in the negative x-direction.
147 Medium
147 of 215
Remembering +4 | -1
Water waves are
View answer and explanation
Correct option: C
Both longitudinal and transverse
Option C (Both longitudinal and transverse) is correct because water waves exhibit both longitudinal and transverse motion of water particles.
148 Medium
148 of 215
Remembering +4 | -1
The minimum audible wavelength at room temperature is about
View answer and explanation
Correct option: D
20  mm20\,\,mm
Option D (20 mm20 \, mm) is correct because the minimum audible frequency is around 20 Hz, and using the speed of sound (approximately 340 m/s), the corresponding wavelength is about 17 meters. The maximum audible frequency is around 20 kHz, which gives a wavelength of approximately 17 mm or roughly 20 mm.
149 Easy
149 of 215
Application +4 | -1
If the initial tension on a stretched string is doubled, then the ratio of the initial and final speeds of a transverse wave along the string is:
View answer and explanation
Correct option: D
1:21:\sqrt 2
Option D (1:21:\sqrt 2) is correct because the speed of a transverse wave is proportional to the square root of the tension.
150 Medium
150 of 215
Understanding +4 | -1
Two waves having sinusoidal waveforms have different wavelengths and different amplitude. They will be having
View answer and explanation
Correct option: C
Different quality and different intensity
Option C is correct because different wavelengths and amplitudes result in different qualities and intensities of sound.
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