Skip to main content
Back to WAVES

Your Progress

0 / 215 Answered
0
Correct
0
Incorrect
0%
Accuracy
NEET • PHYSICS • WAVES

Waves practice · Mixed difficulty

Choose an answer to check it, or open “View answer” to study the explanation. Sign in to save progress to your account.

Practice format and chapter quiz

The practice player uses single-correct-answer MCQs. Chapter quizzes help you review a topic; they are not full-length NEET mock papers.

Take a chapter quiz →
Showing 61-90 of 215 questions

Preparing practice and saved progress…

61 Medium
61 of 215
Application +4 | -1
A wave travelling in positive XX-direction with A=0.2 mA = 0.2\,m has a velocity of 360  m/sec.360\,\,m/sec.. If λ=60  m,\lambda = 60\,\,m,, then correct expression for the wave is
View answer and explanation
Correct option: C
y=0.2sin⁡[2π(6t−x60)]y = 0.2\sin \left[ {2\pi \left( {6t - \frac{x}{{60}}} \right)} \right]
Option C (y=0.2sin⁡[2π(6t−x60)]y = 0.2\sin \left[ {2\pi \left( {6t - \frac{x}{{60}}} \right)} \right]) is correct because it represents a wave traveling in the positive x-direction with the given amplitude, velocity, and wavelength.
62 Medium
62 of 215
Understanding +4 | -1
Learned Indian classical vocalists do not like the accompaniment of a harmonium because
View answer and explanation
Correct option: D
Tempered scale is used in the harmonium
Option D is correct because a tempered scale in a harmonium has fixed intervals, unlike the just intonation preferred by classical vocalists.
63 Medium
63 of 215
Remembering +4 | -1
Sound travels in rocks in the form of:
View answer and explanation
Correct option: C
Both longitudinal and transverse elastic waves
Option C (Both longitudinal and transverse elastic waves) is correct because solids can support both types of waves due to their structure.
64 Easy
64 of 215
Application +4 | -1
The equation of a plane progressive wave is

y=0.09sin⁡8π(t−x20)\mathrm{y}=0.09 \sin 8 \pi\left(\mathrm{t}-\frac{\mathrm{x}}{20}\right)

When it is reflected at rigid supports, its amplitude becomes (2/3)rd of its previous value. The equation of the reflected wave is :
View answer and explanation
Correct option: D
y=−0.06sin⁡8π(t+x20)y=-0.06 \sin 8 \pi\left(t+\frac{x}{20}\right)
Option D is correct because the reflected wave has an amplitude of 0.06, is inverted due to reflection at a rigid support, and travels in the opposite direction.
65 Medium
65 of 215
Understanding +4 | -1
Sound waves in air always longitudinal because
View answer and explanation
Correct option: B
Air does not have a modulus of rigidity
Option B (Air does not have a modulus of rigidity) is correct because longitudinal waves require a medium that can support compression and rarefaction, while transverse waves require a medium with rigidity.
66 Medium
66 of 215
Understanding +4 | -1
To raise the pitch of a stringed musical instrument the player can
View answer and explanation
Correct option: D
Both (2) and (3 )
Option D (Both (2) and (3 )) is correct because tightening the string increases tension and shortening the string decreases the wavelength, both of which increase the frequency (pitch).
67 Medium
67 of 215
Application +4 | -1
A standing wave is formed by the superposition of two waves travelling in opposite directions. The transverse displacement is given by y(x,t)=0.5sin⁡(5π4x)cos⁡(200πt)y\left( {x,t} \right) = 0.5\sin \left( {\frac{{5\pi }}{4}x} \right)\cos \left( {200\pi t} \right). What is the speed of the travelling wave moving in the positive x direction?
View answer and explanation
Correct option: A
160 m/s
Option A (160 m/s) is correct because the speed of the traveling wave is calculated as the ratio of the angular frequency to the wave number, which are extracted from the given standing wave equation.
68 Medium
68 of 215
Application +4 | -1
The length of the wire between two ends of
a sonometer is 100 cm. What should be
the positions of two bridges below the wire
so that the three segments of the wire
have their fundamental frequencies in the
ratio 1 : 3 : 5
View answer and explanation
Correct option: D
150023 cm, 200023 cm\frac{{1500}}{{23}} \, cm,\,\frac{{2000}}{{23}} \, cm
Option D (150023 cm,200023 cm\frac{{1500}}{{23}} \, cm,\frac{{2000}}{{23}} \, cm) is correct because it satisfies the condition where the fundamental frequencies of the three segments are in the ratio 1:3:5.
69 Medium
69 of 215
Analyzing +4 | -1
The equation of the propagating wave is y=25   sin⁡(20t+5x)y = 25\,\,\,\sin \left( {20t + 5x} \right) where yy is displacement. Which of the following statements is not true
View answer and explanation
Correct option: B
The wave is propagating in positive xx-direction
Option B (The wave is propagating in positive xx-direction) is not true because the wave is propagating in the negative x-direction due to the positive sign between the time and position terms in the sine function.
70 Easy
70 of 215
Application +4 | -1
A transverse wave is represented by y=2sin⁡(ωt−kx)cmy=2 \sin (\omega t-k x) \mathrm{cm}. The value of wavelength (in cm\mathrm{cm} ) for which the wave velocity becomes equal to the maximum particle velocity, will be
View answer and explanation
Correct option: A
4π4 \pi
Option A (4π4 \pi) is correct because wave velocity equals maximum particle velocity when wavelength is 4π4 \pi.
71 Medium
71 of 215
Analyzing +4 | -1
A tuning fork of frequency 480  Hz480\,\,Hz produces 10    beats  per  sec\mathrm{10}{\mkern 1mu} {\mkern 1mu} \,\,\mathrm{beats}\,\,\mathrm{per}\,\,\mathrm{sec} when sounded with a vibrating sonometer string. What must have been the frequency of string if slight increase in tension produces few beats s−1{\mathrm{s}^{ - 1}} than before?
View answer and explanation
Correct option: B
470  Hz \begin{array}{llllllllllllllllllll} {470\,\,Hz} \end{array}\,
Option B (470 Hz) is correct because the frequency of the string must be lower than the tuning fork's frequency, and increasing tension reduces the beat frequency.
72 Easy
72 of 215
Understanding +4 | -1
What is your observation when two sources are emitting sound with frequency 499 Hz499 \mathrm{~Hz} and 501 Hz501 \mathrm{~Hz}?
View answer and explanation
Correct option: A
Frequency of 500 Hz500 \mathrm{~Hz} is heard with change in intensity take place twice
Option A (Frequency of 500 Hz is heard with change in intensity take place twice) is correct because the average frequency is 500 Hz and the beat frequency (change in intensity) is 2 Hz, meaning the intensity changes twice per second.
73 Medium
73 of 215
Analyzing +4 | -1
The displacement yy of a particle is given by y=4  cos⁡2(t2)  sin⁡(1000t)y = 4\,\,{\cos ^{ 2}}\left( {\frac{t}{2}} \right)\,\,\sin \left( {1000t} \right). This expression may be considered to be a result of the superposition of how many simple harmonic motions?
View answer and explanation
Correct option: B
33
Option B (3) is correct because the given expression can be rewritten as a superposition of three simple harmonic motions using trigonometric identities.
74 Medium
74 of 215
Remembering +4 | -1
Frequency range of the audible sound is
View answer and explanation
Correct option: B
20 Hz−20 kHz20 \mathrm{~Hz}-20 \mathrm{~kHz}
Option B (20 Hz−20 kHz20 \mathrm{~Hz}-20 \mathrm{~kHz}) is correct because it represents the typical range of human hearing.
75 Medium
75 of 215
Analyzing +4 | -1
The transverse displacement y(x,t)y\left( {x,t} \right) of a wave on a string is given by y(x,t)=e−(ax2+bt2+2abxt)y\left( {x,t} \right) = {e^{ - \left( {a{x^2} + b{t^2} + 2\sqrt {ab} xt} \right)}} This represent a
View answer and explanation
Correct option: A
Wave moving in xx- direction with speed ba\sqrt {\frac{b}{a}}
Option A (Wave moving in xx- direction with speed ba\sqrt {\frac{b}{a}}) is correct because the given equation represents a wave moving along the x-axis, and the speed can be determined from the coefficients of x and t.
76 Hard
76 of 215
Application +4 | -1
Two wires of different densities but same area of cross section are soldered together at one end and are stretched to a tension TT. The velocity of a transverse wave in the first wire is double of that in the second wire. Find the ratio of the density of the first wire to that of the second wire.
View answer and explanation
Correct option: A
0.25
Option A (0.25) is correct because the ratio of densities is inversely proportional to the square of the velocities.
77 Medium
77 of 215
Application +4 | -1
In a transverse progressive wave of amplitude A, the maximum particle velocity is four times its wave velocity. The wavelength of the wave is:-
View answer and explanation
Correct option: B
πA2\frac{{\pi A}}{2}
Option B (πA2\frac{{\pi A}}{2}) is correct because the wavelength is derived from the relationship between maximum particle velocity, wave velocity, and amplitude.
78 Medium
78 of 215
Application +4 | -1
When a sound wave of wavelength λ\lambda is propagating in a medium, the maximum velocity of the particle is equal to the velocity. The amplitude of wave is
View answer and explanation
Correct option: C
λ2π\frac{\mathrm{\lambda }}{{2\mathrm{\pi }}}
Option C (λ2π\frac{\mathrm{\lambda }}{{2\mathrm{\pi }}}) is correct because the amplitude is related to the wavelength when the maximum particle velocity equals the wave velocity.
79 Medium
79 of 215
Application +4 | -1
If the temperature is raised by 1K1\mathrm{ }K from 300K300\mathrm{ }K the percentage change in the speed of sound in the gaseous mixture is (R=8.31J/mol−K)\left( {R = 8.31\mathrm{ }J/mol - K} \right)
View answer and explanation
Correct option: A
0.00167
Option B (0.00334) is correct because it represents the percentage change in the speed of sound calculated using the temperature dependence of sound velocity.
80 Medium
80 of 215
Application +4 | -1
The equation of a simple harmonic progressive wave is given by y=A  sin(100−3x)y = A\,\,sin(100 - 3x). find the distance between 22 particles having a phase difference of π3\frac{\pi }{3}.
View answer and explanation
Correct option: A
π9m\frac{\mathrm{\pi }}{9}\mathrm{m}
Option A (π9m\frac{\mathrm{\pi }}{9}\rm{{m}}) is correct because it represents the distance corresponding to the given phase difference, calculated using the wave number.
81 Medium
81 of 215
Application +4 | -1
A sonometer is set on the floor of a lift. When the lift is at rest, the sonometer wire vibrates with fundamental frequency 256 Hz. When the lift goes up with acceleration a=9g16a = \frac{{9g}}{{16}} vibration of the same wire changes to
View answer and explanation
Correct option: B
320 Hz
Option B (320 Hz) is correct because the frequency of the sonometer wire is proportional to the square root of the tension, and the effective weight increases with upward acceleration.
82 Hard
82 of 215
Application +4 | -1
A sinusoidal wave of wavelength 7.5 cm travels a distance of 1.2 cm along the x-direction in 0.3 sec. The crest PP is at x=0x=0 at t=0 sect=0 \mathrm{~sec} and maximum displacement of the wave is 2 cm. Which equation correctly represents this wave?
View answer and explanation
Correct option: A
y=2cos⁡(0.83x−3.35t)cmy=2 \cos (0.83 x-3.35 t) \mathrm{cm}
Option A (π2\frac{\pi }{2}) is correct because the phase difference between sin⁡(θ)\sin(\theta) and cos⁡(θ)\cos(\theta) is π2\frac{\pi}{2}.
83 Medium
83 of 215
Analyzing +4 | -1
Two waves travelling in a medium in the x-direction are represented by , y1=Asin⁡(αt−βx){y_1} = A\sin \left( {\alpha t - \beta x} \right) and y2=Acos⁡(βx+αt−π/4){y_2} = A\cos \left( {\beta x + \alpha t - \pi /4} \right) where y1    and  y2{y_1}\;\,\,and\,\,\mathrm{ }{y_2} are the displacements of the particles of the medium, t is time, and  α and β\alpha \,and\,\beta are constants. The two waves have different
View answer and explanation
Correct option: B
Directions of propagation
Option B (Directions of propagation) is correct because the sign difference between the time and position terms in the wave equations determines the direction of propagation.
84 Medium
84 of 215
Understanding +4 | -1
Which two of the given transverse waves will give stationary waves when get superimposed
z1=acos⁡(kx−ωt){z_1} = a\cos \left( {kx - \omega t} \right) …(AA)
z2=acos⁡(kx+ωt){z_2} = a\cos \left( {kx + \omega t} \right) …(BB)
z3=acos⁡(ky−ωt){z_3} = a\cos \left( {ky - \omega t} \right) …(CC)
View answer and explanation
Correct option: A
A  and  B\begin{array}{llllllllllllllllllll} {A\,\,and\,\,B} \end{array}
Option A (A and B) is correct because stationary waves are formed by the superposition of two waves with the same amplitude and frequency traveling in opposite directions, which is the case with z1 and z2.
85 Easy
85 of 215
Understanding +4 | -1
The engineer of a train blows the train whistle as he approaches a crossing. A few moments later he hears a echo from the whistle. The engineer hears the echo of the whistle because of:
View answer and explanation
Correct option: A
Reflection
Option A (Reflection) is correct because the echo is the result of the sound wave bouncing off a surface and returning to the source.
86 Medium
86 of 215
Application +4 | -1
A uniform string of length 12m and mass 6kg hangs from a rigid support. A block of mass 2 kg is attached to the free end. A transverse pulse of wavelength 0.06 m is produced at the lower end of the rope. What is the wavelength of pulse when it reaches to top of string?
View answer and explanation
Correct option: C
0.12 m
Option C (0.12 m) is correct because the wavelength increases as the velocity of the pulse increases due to increasing tension towards the top of the string.
87 Medium
87 of 215
Application +4 | -1
Two monochromatic coherent light beams A and B have intensities II and I4\frac{I}{4} respectively. If these waves are superposed, the maximum and minimum intensities will be
View answer and explanation
Correct option: A
9I4,I4\frac{{9I}}{4},\frac{I}{4}
Option A (9I4,I4\frac{{9I}}{4},\frac{I}{4}) is correct because the maximum intensity is proportional to the square of the sum of the amplitudes, and the minimum intensity is proportional to the square of the difference of the amplitudes.
88 Medium
88 of 215
Remembering +4 | -1
Law of superposition is applicable to
View answer and explanation
Correct option: D
All kinds of waves
Option D (All kinds of waves) is correct because the principle of superposition applies to all types of waves, including light, sound, and transverse waves.
89 Medium
89 of 215
Understanding +4 | -1
The following phenomenon cannot be observed for sound waves
View answer and explanation
Correct option: D
Polarization
Option D (Polarization) is correct because polarization is a phenomenon specific to transverse waves, and sound waves are longitudinal.
90 Medium
90 of 215
Understanding +4 | -1
A heavy rope is suspended from rigid support A wave pulse is set up at the lower end. Then
View answer and explanation
Correct option: B
The pulse will travel with increasing speed
Option B (The pulse will travel with increasing speed) is correct because the tension in the rope increases as the pulse travels upwards, leading to an increase in wave speed.
Revision notes and key takeaways

Review WAVES in your textbook or class notes, then use this set to check your understanding.

Showing 61-90 of 215 questions

Your practice

0 / 215 answered · 215 remaining · 0% accuracy

Progress is stored on this device. Sign in to save to your account.

✓ Correct · ✗ Incorrect · ○ Unanswered

Answer feedback and difficulty

Type at least 2 characters or jump directly:
🔓

Save your learning progress

Sign in with a free account to save your practice answers and quiz results, then return to them when you revise.