Back to WAVE OPTICS

Your Progress

0 / 150 Answered

Correct

Incorrect

Accuracy

NEET • PHYSICS • WAVE OPTICS

Wave optics practice · Mixed difficulty

Try a question, then open “View answer” to check it. Sign in to submit answers and save progress.

Practice format and chapter quiz

The practice player uses single-correct-answer MCQs. Chapter quizzes help you review a topic; they are not full-length NEET mock papers.

Take a chapter quiz →

Showing 1-30 of 150 questions

1 Easy

1 of 150

Application +4 | -1

Two waves of amplitude

5 \mathrm{~mm}

and

7 \mathrm{~mm}

reach a point in opposite phase. The resultant amplitude is

View answer and explanation

Correct option: C

2 \mathrm{~mm}

Option C (2 mm) is correct because when waves are in opposite phase, the resultant amplitude is the difference between the individual amplitudes.

2 Medium

2 of 150

Remembering +4 | -1

H-polaroid is prepared by

View answer and explanation

Correct option: D

Stretching polyvinyl alcohol and then impregnation with iodine

Option D (Stretching polyvinyl alcohol and then impregnation with iodine) is correct because this is the standard method for creating H-polaroid.

3 Medium

3 of 150

Understanding +4 | -1

Evidence for the wave nature of light cannot be obtained from

View answer and explanation

Correct option: A

Reflection

Option A (Reflection) is correct because reflection can be explained by both wave and particle nature of light, and doesn't uniquely demonstrate wave nature.

4 Medium

4 of 150

Remembering +4 | -1

Which radiation in sunlight, causes heating effect

View answer and explanation

Correct option: B

Infrared

Option B (Infrared) is correct because infrared radiation is primarily responsible for the heating effect of sunlight.

5 Medium

5 of 150

Understanding +4 | -1

In the propagation of light waves, the angle between the direction of vibration and plane of polarization is

View answer and explanation

Correct option: A

0^\circ

Option A is correct. The direction of vibration and the plane of polarization are always parallel, hence the angle between them is 0°.

6 Medium

6 of 150

Understanding +4 | -1

In Young’s experiment, one slit is covered with a blue filter and the other (slit) with a yellow filter. Then the interference pattern

View answer and explanation

Correct option: D

Will not be formed

Option D (Will not be formed) is correct because interference requires coherent sources, and using different colored filters makes the sources incoherent.

7 Easy

7 of 150

Analyzing +4 | -1

Four independent light waves are expressed as

\mathrm{y}_1=\mathrm{a}_1 \sin \omega \mathrm{t}, \mathrm{y}_2=\mathrm{a}_2 \sin \omega \mathrm{t}, \mathrm{y}_3=\mathrm{a}_3 \cos \omega \mathrm{t}

and

\mathrm{y}_4=\mathrm{a}_4 \sin (\omega \mathrm{t}+\pi / 3)

. The interference is possible between

View answer and explanation

Correct option: D

Not possible at all

Option D (Not possible at all) is correct because for interference to occur, the waves must have the same frequency and a constant phase relationship. Waves 1 and 2 are in phase, wave 3 is in quadrature, and wave 4 has a constant phase shift, but none of these pairs can produce sustained interference.

8 Hard

8 of 150

Remembering +4 | -1

In Young’s double slit experiment, a minimum is obtained when the phase difference of superimposing waves is

View answer and explanation

Correct option: B

\left( {2n - 1} \right)\pi

Option B is correct. A minimum (destructive interference) is obtained when the phase difference is an odd multiple of

\pi

, represented as

(2n - 1)\pi

9 Easy

9 of 150

Application +4 | -1

A beam of monochromatic light of wavelength

5.82 \times 10^{-7} \mathrm{~m}

falls normally on a glass wedge with the wedge angle of 20 second of an arc. If the refractive index of glass is

1.5,

find the number of dark interference fringes per

\mathrm{cm}

of the wedge length:

View answer and explanation

Correct option: B

5 per cm

Option B (5 per cm) is correct because the fringe width is calculated using the wedge angle and refractive index, then the number of fringes per cm is found.

10 Hard

10 of 150

Application +4 | -1

The sodium yellow doublet has wavelengths

5890 \mathrm{~A}^0

and

\lambda \mathrm{~A}^0

and resolving power of a grating to resolve these lines is 982, then value of

\lambda

View answer and explanation

Correct option: A

5896 \mathrm{~A}^0

Option A (

5896 \mathrm{~A}^0

) is correct because it is calculated using the resolving power formula for a grating.

11 Medium

11 of 150

Remembering +4 | -1

Which of the following is a dichroic crystal?

View answer and explanation

Correct option: B

Tourmaline

Tourmaline is a dichroic crystal, meaning it exhibits different colors when viewed from different directions due to selective absorption of light.

12 Medium

12 of 150

Analyzing +4 | -1

Assertion: We cannot observe diffraction pattern from a wide slit iluminated by monochromatic light.

Reason: In diffraction pattern, all the bright bands are not of the same intensity.

View answer and explanation

Correct option: B

Both Assertion and Reason are true and Reason is not the correct explanation of Assertion

Option B (Both Assertion and Reason are true and Reason is not the correct explanation of Assertion) is correct because both statements are true, but the reason does not explain the assertion.

13 Easy

13 of 150

Application +4 | -1

In a Young's double slit experiment the slit separation is

0.5 \mathrm{~mm}

and the screen is

0.5 \mathrm{~m}

from the slit. For a monochromatic light of wavelength

500 \mathrm{~nm}

the distance of

3^{\text {rd}}

maxima from the

2^{\text {nd}}

minima on the other side is:

View answer and explanation

Correct option: D

2.25 mm

The correct answer is D (2.25 mm) because it is the calculated distance between the 3rd maxima and the 2nd minima on the opposite side in Young's double slit experiment.

14 Medium

14 of 150

Remembering +4 | -1

The resolving limit of healthy eye is about

View answer and explanation

Correct option: A

1'

{\left( {\frac{1}{{60}}} \right)^0}

Option A is correct. The resolving limit of a healthy human eye is approximately 1 minute of arc, or (1/60) of a degree.

15 Medium

15 of 150

Understanding +4 | -1

A Young’s double slit set up for interference is shifted from air to within water, then the fringe width

View answer and explanation

Correct option: B

Decreases

When a Young's double-slit setup is moved from air to water, the wavelength of light decreases, causing the fringe width to decrease as well. The refractive index of water is greater than air.

Explore Other Chapters in PHYSICS

View All →

UNITS & MEASUREMENTS 392 MCQs WORK-ENERGY-POWER 355 MCQs MECHANICAL PROPERTIES OF FLUIDS 317 MCQs MOTION IN PLANE 307 MCQs MAGNETIC EFFECT OF CURRENT 282 MCQs THERMAL PROPERTIES OF MATTER 269 MCQs

16 Medium

16 of 150

Remembering +4 | -1

The coherent formula for fringe visibility is

View answer and explanation

Correct option: A

V = \frac{{{I_{\max }} - {I_{\min }}}}{{{I_{\max }} + {I_{\min }}}}

Option A is correct. Fringe visibility is defined as

V = \frac{{{I_{\max }} - {I_{\min }}}}{{{I_{\max }} + {I_{\min }}}}

which quantifies the contrast between the brightest and darkest fringes.

17 Medium

17 of 150

Understanding +4 | -1

Light waves travel in vacuum along the

y - \mathrm{axis}

. Which of the following may represent the wavefront?

View answer and explanation

Correct option: A

y = constant

Option A (

y = constant

) is correct because a wavefront is a surface of constant phase, and if light travels along the y-axis, the wavefront is perpendicular to it.

18 Easy

18 of 150

Application +4 | -1

A microwave of wavelength

2.0 \mathrm{~cm}

falls normally on a slit of width

4.0 \mathrm{~cm}

. The angular spread of the central maxima of the diffraction pattern obtained on a screen

1.5 \mathrm{~m}

away from the slit, will be

View answer and explanation

Correct option: C

60^{\circ}

Option C (

60^{\circ}

) is correct because the angular spread of the central maxima is given by

2\theta

, where

\sin \theta = \frac{\lambda}{a}

19 Medium

19 of 150

Understanding +4 | -1

The phase difference between incident wave and reflected wave is

180^\circ

when light ray

View answer and explanation

Correct option: A

Enters into glass from air

Option A (Enters into glass from air) is correct because when light travels from a rarer to a denser medium, it undergoes a phase change of 180 degrees upon reflection.

20 Medium

20 of 150

Understanding +4 | -1

The fringe width in Young’s double slit experiment increases when

View answer and explanation

Correct option: A

Wavelength increases

The fringe width in Young's double-slit experiment increases when the wavelength increases. The fringe width is directly proportional to the wavelength of light.

21 Medium

21 of 150

Remembering +4 | -1

Light is an electromagnetic wave. Its speed in vacuum is given by the expression

View answer and explanation

Correct option: D

\frac{1}{{\sqrt {{\mu _o}{\varepsilon _o}} }}

Option D is correct. The speed of light in a vacuum is given by the formula c = 1/√(μ₀ε₀).

22 Medium

22 of 150

Application +4 | -1

Light propagates

2\;cm

distance in glass of refractive index 1.5 in time

{t_0}

. In the same time

{t_0}

, light propagates a distance of

2.25\;cm

in a medium. The refractive index of the medium is

View answer and explanation

Correct option: A

4/3

Option A (

4/3

) is correct because it is calculated using the relationship between refractive index, speed of light, and distance traveled.

23 Medium

23 of 150

Application +4 | -1

Critical angle for certain medium is

{\sin ^{ - 1}}\left( {0.6} \right).

The polarizing angle of that medium is

View answer and explanation

Correct option: C

{\tan ^{ - 1}}\left[ {1.6667} \right]

The correct answer is C (

{\tan ^{ - 1}}\left[ {1.6667} \right]

) because it is the Brewster's angle calculated from the refractive index, which is derived from the critical angle.

24 Hard

24 of 150

Application +4 | -1

For what distance is ray optics a good approximation when the aperture is 4mm wide and the wave length is 500 nm

View answer and explanation

Correct option: A

32 m

Option A (32 m) is correct because it is calculated using the Fresnel distance formula.

25 Easy

25 of 150

Application +4 | -1

Using Young's double slit experiment, a monochromatic light of wavelength

5000\mathop {\text{A}}\limits^{\text{o}}

produces fringes of fringe width

0.5 \mathrm{~mm}

. If another monochromatic light of wavelength

6000\mathop {\text{A}}\limits^{\text{o}}

is used and the separation between the slits is doubled, then the new fringe width will be :

View answer and explanation

Correct option: D

0.3 \mathrm{~mm}

Option C (

0.6 \mathrm{~mm}

) is correct because the fringe width is directly proportional to the wavelength and inversely proportional to the slit separation; doubling the slit separation and changing the wavelength results in a new fringe width of 0.6 mm.

26 Medium

26 of 150

Application +4 | -1

Two point white does are

\mathrm{1}\,\,\mathrm{mm}

apart on a black paper. They are viewed by eye of pupil diameter

\mathrm{3}\,\,\mathrm{mm}

. Approximately, what is the maximum distance at which these dots can be resolved by the eye? [Take wavelength of light

\mathrm{ = 500}\,\,\mathrm{nm}

]

View answer and explanation

Correct option: A

\mathrm{5}\,\,\mathrm{m}

Option A (

\mathrm{5}\,\mathrm{m}

) is correct because it is calculated using the resolution limit formula.

27 Medium

27 of 150

Remembering +4 | -1

Fringe pattern in YDSE is formed due to the phenomenon of

View answer and explanation

Correct option: C

Interference of light

Option C (Interference of light) is correct because the fringe pattern in YDSE is a direct result of the interference of light waves.

28 Medium

28 of 150

Application +4 | -1

In Fresnel’s biprism experiment is held in water instead of air, then what will be the effect on fringe width

View answer and explanation

Correct option: B

Increases

Option A (Decreases) is correct because the fringe width is inversely proportional to the refractive index of the medium.

29 Medium

29 of 150

Understanding +4 | -1

Which one of the following phenomena is not explained by Huygen’s construction of wavefront

View answer and explanation

Correct option: D

Origin of spectra

Option D (Origin of spectra) is correct because Huygens' principle primarily explains wave propagation, reflection, refraction, and diffraction, not the origin of spectra which is related to atomic structure and quantum mechanics.

30 Medium

30 of 150

Understanding +4 | -1

The phenomenon which does not take place in sound waves is

View answer and explanation

Correct option: D

Polarisation

Polarization is a phenomenon that only occurs with transverse waves, such as light waves. Sound waves are longitudinal waves and cannot be polarized.

Revision notes and key takeaways

Review WAVE OPTICS in your textbook or class notes, then use this set to check your understanding.

Key Takeaways

✓ This set contains 150 single-correct-answer MCQs on WAVE OPTICS.
✓ Try each question before opening its answer. Read the explanation where one is available.
✓ Sign in to save submitted answers. Revisit incorrect answers alongside your textbook or class notes.

Showing 1-30 of 150 questions

Continue Your Practice

📚 Switch Set (ALL)

Chapter Sets

ALL 150 MCQs EASY 25 MCQs HARD 16 MCQs MEDIUM 109 MCQs

0 /150

0✓ 0✗

0% Accuracy