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NEET • PHYSICS • WAVE OPTICS
Wave optics practice · Mixed difficulty
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121
Easy
121 of 150
Analyzing
+4 | -1
Statement-1: In YDSE, if separation between slits is less than wavelength of light, then no interference pattern could be observed.
Statement-2: For interference pattern to be observed, light sources have to be coherent.
Statement-2: For interference pattern to be observed, light sources have to be coherent.
View answer and explanation
Correct option: B
Statement-1 is true, Statement-2 is true, Statement-2 is not the correct explanation for Statement-1
Option B is correct. Statement-1 is true because if the slit separation is less than the wavelength, no distinct interference pattern is formed. Statement-2 is also true because coherent sources are necessary for sustained interference, but the coherence is not the direct reason for the absence of a pattern when slit separation is less than the wavelength.
122
Medium
122 of 150
Understanding
+4 | -1
A single slit is used to observe diffraction pattern with red light. On replacing the red light with violet light the diffraction pattern would
View answer and explanation
Correct option: B
Become narrower
Option B (Become narrower) is correct because violet light has a shorter wavelength than red light, resulting in a smaller diffraction angle and thus a narrower pattern.
123
Medium
123 of 150
Application
+4 | -1
Two stars are situated at a distance of 8 light year from the earth. These are to be just resolved by a telescope of diameter . If the wavelength of light used is , then the distance between the stars must be
View answer and explanation
Correct option: C
Option C () is correct because it is calculated using the resolving power formula and the given parameters.
124
Medium
124 of 150
Analyzing
+4 | -1
A stone thrown into still water, creates a circular wave pattern moving radially outwards. If is the distance measured from the centre of the pattern, the amplitude of the wave varies as
View answer and explanation
Correct option: B
Option B () is correct because the amplitude of a circular wave decreases inversely with the distance from the center due to energy conservation.
125
Medium
125 of 150
Analyzing
+4 | -1
Yellow light is used in single slit diffraction experiment with slit width . If yellow light is replaced by -rays, then the pattern will reveal that
View answer and explanation
Correct option: A
No diffraction pattern
Option A (No diffraction pattern) is correct because the wavelength of X-rays is much smaller than the slit width, resulting in negligible diffraction.
126
Medium
126 of 150
Remembering
+4 | -1
Newton postulated his corpuscular theory on the basis of
View answer and explanation
Correct option: C
Rectilinear propagation of light
Option C (Rectilinear propagation of light) is correct because Newton's corpuscular theory explained light as particles traveling in straight lines.
127
Medium
127 of 150
Remembering
+4 | -1
Refractive index of material is equal to tangent of polarising angle. It is called
View answer and explanation
Correct option: A
Brewster's law
Option A (Brewster's law) is correct because Brewster's law states that the refractive index is equal to the tangent of the polarizing angle.
128
Medium
128 of 150
Application
+4 | -1
Two waves coming from two coherent sources, having different intensities interfere their ratio of maximum intensity to the minimum intensity is . The intensities of the sources are in the ratio
View answer and explanation
Correct option: C
The correct answer is C () because it represents the ratio of intensities derived from the given ratio of maximum to minimum intensity.
129
Medium
129 of 150
Application
+4 | -1
The first diffraction minima due to a single slit diffraction is at for a light of wavelength . The width of the slit is
View answer and explanation
Correct option: B
Option B () is correct because it is calculated using the formula for the first diffraction minima in single-slit diffraction.
130
Medium
130 of 150
Understanding
+4 | -1
A diffraction pattern is obtained using a beam of red light. What happens if the red light is replaced by blue light
View answer and explanation
Correct option: B
Diffraction bands become narrower and crowded together
Option B (Diffraction bands become narrower and crowded together) is correct because blue light has a shorter wavelength than red light, leading to smaller diffraction angles.
131
Medium
131 of 150
Remembering
+4 | -1
Which of the following is not a property of light
View answer and explanation
Correct option: A
It requires a material medium for propagation
Option A (It requires a material medium for propagation) is correct because light is an electromagnetic wave and does not require a medium to travel.
132
Medium
132 of 150
Application
+4 | -1
In a two slit experiment with monochromatic light fringes are obtained on a screen placed at some distance from the slits. If the screen is moved by towards the slits, the change in fringe width is . If separation between the slits is the wavelength of light used is
View answer and explanation
Correct option: A
Option A () is correct because it is calculated using the change in fringe width and the change in distance to the slits.
133
Medium
133 of 150
Analyzing
+4 | -1
In Young’s double slit experiment the wavelength of light was changed from . While doubling the separation between the slits which of the following is not true for this experiment
View answer and explanation
Correct option: D
The separation between successive dark fringes remains unchanged
Option D (The separation between successive dark fringes remains unchanged) is correct because when the wavelength is halved and the slit separation is doubled, the fringe width remains the same, so the separation between successive dark fringes also remains unchanged.
134
Medium
134 of 150
Remembering
+4 | -1
Wavefront means
View answer and explanation
Correct option: A
All particles in it have same phase
Option A (All particles in it have same phase) is correct because a wavefront is defined as a surface containing points affected by a wave in the same phase.
135
Medium
135 of 150
Application
+4 | -1
Intensity of central maxima in Young’s double slit experiment is found to be 20 units. Then intensity at a point where phase difference between identical interfering waves is is
View answer and explanation
Correct option: A
10 unit
Option A (10 unit) is correct because the intensity is calculated using the formula with the given phase difference.
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136
Medium
136 of 150
Analyzing
+4 | -1
Assertion : When light ray is incident at polarizing angle on glass, reflected light is partially polarized.
Reason : The intensity of light decreases in polarization.
Reason : The intensity of light decreases in polarization.
View answer and explanation
Correct option: D
If both Assertion and reason are false
Option D is correct. When light is incident at the polarizing angle on glass, the reflected light is completely polarized, not partially polarized. Also, the intensity of light decreases after polarization.
137
Medium
137 of 150
Remembering
+4 | -1
Light waves can be polarized as they are
View answer and explanation
Correct option: A
Transverse
Light waves can be polarized because they are transverse waves. Polarization is a phenomenon exhibited by transverse waves, not longitudinal waves.
138
Medium
138 of 150
Analyzing
+4 | -1
Statement-1: Two thirds of possible values for phase difference result in constructive interference and one third results in destructive interference.
Statement-2: Interference is called constructive if the amplitude of the superposed waves exceeds that of one individual wave.
Statement-2: Interference is called constructive if the amplitude of the superposed waves exceeds that of one individual wave.
View answer and explanation
Correct option: A
Statement-1 is true, Statement-2 is true, Statement-2 is the correct explanation for Statement-1
Option A is correct because constructive interference occurs when the phase difference is a multiple of , and destructive interference occurs when the phase difference is an odd multiple of .
139
Medium
139 of 150
Analyzing
+4 | -1
Assertion : In YDSE the fringe separation doesn’t contain any information about intensity of individual source.
Reason : Fringe width depends on wavelength of source.
Reason : Fringe width depends on wavelength of source.
View answer and explanation
Correct option: B
If both Assertion and Reason are true but Reason is not a correct explanation of the Assertion
Option B is correct. The fringe separation in YDSE doesn't directly contain information about the intensity of individual sources, and the fringe width depends on the wavelength of the source. However, the wavelength dependency doesn't explain why the intensity is not directly contained in the fringe separation.
140
Medium
140 of 150
Remembering
+4 | -1
The solar spectrum during a complete solar eclipse is
View answer and explanation
Correct option: A
Continuous
Option A is correct. During a complete solar eclipse, the solar spectrum is continuous because the corona is still emitting light.
141
Hard
141 of 150
Application
+4 | -1
Specific rotation of sugar solution is of impure sugar solution is taken in a sample polarimeter tube of length and optical rotation is found to be . The percentage of purity of sugar is
View answer and explanation
Correct option: C
The correct answer is C () because it is the calculated percentage of purity of the sugar solution based on the given specific rotation and observed rotation.
142
Easy
142 of 150
Understanding
+4 | -1
Assertion: Incoming light reflected by earth is partially polarized.
Reason: Atmospheric particle polarize the light.
Reason: Atmospheric particle polarize the light.
View answer and explanation
Correct option: A
If both Assertion and Reason are true and Reason is the correct explanation of Assertion
Both the Assertion and Reason are true, and the Reason is the correct explanation of the Assertion. Atmospheric particles scatter sunlight, and this scattering causes the reflected light to be partially polarized.
143
Medium
143 of 150
Analyzing
+4 | -1
Assertion (A) : For two sources to be coherent phase difference between two waves at all points should be same.
Reason (R) : Two different light sources are never coherent.
Reason (R) : Two different light sources are never coherent.
View answer and explanation
Correct option: D
If Assertion is false but the Reason is true.
Option D is correct. The assertion is false because coherent sources can have a constant phase difference, not necessarily zero. The reason is true because two independent light sources cannot maintain a constant phase relationship.
144
Medium
144 of 150
Understanding
+4 | -1
Select the right option in the following
View answer and explanation
Correct option: B
Maxwell provided the theoretical evidence that light is transverse wave
Option B (Maxwell provided the theoretical evidence that light is transverse wave) is correct because Maxwell's equations demonstrated that light is an electromagnetic wave, and electromagnetic waves are transverse.
145
Medium
145 of 150
Understanding
+4 | -1
Two light sources are said to be coherent if they are obtained from
View answer and explanation
Correct option: B
A single point source
Option B (A single point source) is correct because deriving the two sources from a single source ensures they have a constant phase relationship, hence coherence.
146
Medium
146 of 150
Understanding
+4 | -1
The separation between two microscopic particles is measured and by two different lights of wavelength and respectively, then
View answer and explanation
Correct option: B
Option B is correct. Resolving power is inversely proportional to the wavelength of light used. Therefore, smaller wavelength light (2000 Å) will have better resolving power and thus smaller resolvable distance.
147
Easy
147 of 150
Application
+4 | -1
A glass plate thick is placed in the path of one of the interfering beams in a Young's double slit interference arrangement using monochromatic light of wavelength . If the central band shifts a distance equal to width of 10 bands. What is the thickness (in ) of the plate of diamond of refractive index that has to be introduced in the path of second beam to bring the central band to original position?
View answer and explanation
Correct option: A
4
Option A (4) is correct because the optical path difference introduced by the glass plate must be compensated by the diamond plate.
148
Hard
148 of 150
Application
+4 | -1
A beam of light consisting of wavelengths and is used in a YDSE with D=1m and d=1 . Find the least distance from the central maxima, where bright fringes due to the two wavelengths coincide.
View answer and explanation
Correct option: C
Option C () is correct because it represents the least distance where bright fringes of the two wavelengths coincide, calculated using the condition for constructive interference in YDSE.
149
Medium
149 of 150
Analyzing
+4 | -1
Assertion : Resolving power of a telescope depends only on wavelength.
Reason : This is proportional to square of wavelength.
Reason : This is proportional to square of wavelength.
View answer and explanation
Correct option: D
If both Assertion and reason are false
Option D (If both Assertion and reason are false) is correct because the resolving power of a telescope depends on the wavelength and the diameter of the objective lens, and it is inversely proportional to the wavelength, not proportional to the square of the wavelength.
150
Hard
150 of 150
Application
+4 | -1
For what distance is ray optics a good approximation when the aperture is wide and wavelength is
View answer and explanation
Correct option: A
Option A () is correct because it is calculated using the Fresnel distance formula, which determines the distance for which ray optics is a good approximation.
Revision notes and key takeaways
Review WAVE OPTICS in your textbook or class notes, then use this set to check your understanding.
Showing 121-150 of 150 questions
