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NEET • PHYSICS • SYSTEM OF PARTICLES

System of particles practice · Medium

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121 Medium
121 of 157
Analyzing +4 | -1
S-I: In rolling, all points of a rigid body have the same linear speed.
S-II: The rotational motion does not affect the linear velocity of rigid body.
View answer and explanation
Correct option: D
Both S-I and S-II are incorrect
Option D is correct because in rolling motion, points on a rigid body have different linear speeds and rotational motion affects the linear velocity.
122 Medium
122 of 157
Understanding +4 | -1
A body falling vertically downwards under gravity breaks in two parts of unequal masses. The centre of mass of the two parts taken together shifts horizontally towards
View answer and explanation
Correct option: C
does not shift horizontally
Option C (does not shift horizontally) is correct because the explosion is an internal force, and internal forces do not affect the motion of the center of mass.
123 Medium
123 of 157
Understanding +4 | -1
A loded spring gun of mass M fires a shot of mass m with a velocity v at an angle of elevation θ\theta. The gun was initially at rest on a horizontal frictionless surface. After firing, the centre of mass of gun-shot system
View answer and explanation
Correct option: C
Remain at rest
Option C (Remain at rest) is correct because there are no external forces acting on the gun-shot system in the horizontal direction, so the center of mass remains at rest.
124 Medium
124 of 157
Understanding +4 | -1
A mass is revolving in a circle which is in the plane of paper. The direction of angular acceleration is
View answer and explanation
Correct option: A
Upward the radius
Option D (At right angle to angular velocity) is correct because angular acceleration is perpendicular to angular velocity when the magnitude of angular velocity changes.
125 Medium
125 of 157
Remembering +4 | -1
What is the moment of inertia of solid sphere of density ρ\rho and radius R about its diameter?
View answer and explanation
Correct option: C
176105R5ρ\frac{{176}}{{105}}{R^5}\mathrm{\rho }
Option C (176105R5ρ\frac{{176}}{{105}}{R^5}\mathrm{\rho }) is correct because it represents the moment of inertia of a solid sphere in terms of its density and radius, derived using the formula for moment of inertia and the relationship between mass, density, and volume.
126 Medium
126 of 157
Understanding +4 | -1
In free space, a shell moving with velocity 60 m/s60\,m/s along the positive x-axis. When it passes through origin, it explodes into two pieces of mass ratio 1: 2. After the explosion, the velocity of the centre of mass is:-
View answer and explanation
Correct option: B
60 m/s60\,m/s
Option B is correct. The velocity of the center of mass remains constant unless acted upon by an external force. Since the shell explodes due to internal forces, the velocity of the center of mass remains the same, which is 60 m/s.
127 Medium
127 of 157
Analyzing +4 | -1
What happens to the centripetal acceleration of a particle, when its speed is doubled and angular velocity is halved?
View answer and explanation
Correct option: C
Remains unchanged
Option C (Remains unchanged) is correct because centripetal acceleration is given by ac=vωa_c = v\omega, and doubling the speed and halving the angular velocity cancels out, leaving the acceleration unchanged.
128 Medium
128 of 157
Application +4 | -1
A particle is under uniform circular motion with angular momentum L. If its kinetic energy is tripled and frequency of motion is halved then new angular momentum becomes
View answer and explanation
Correct option: D
6 L
Option D (6 L) is correct. Angular momentum is related to kinetic energy and frequency, and changing these parameters affects the angular momentum.
129 Medium
129 of 157
Application +4 | -1
From a circular disc of radius R and mass 4m, a small disc of radius R2\frac{R}{2} is removed concentrically. The moment of inertia of the remaining disc about an axis perpendicular to the plane of the disc and passing through its centre is
View answer and explanation
Correct option: B
158mR2\frac{{15}}{8}m{R^2}
Option B (15/8 mR²) is correct because it is the result of subtracting the moment of inertia of the removed disc from the original disc.
130 Medium
130 of 157
Understanding +4 | -1
Moment of inertia of an object does not depend upon
View answer and explanation
Correct option: C
Angular velocity
Option C (Angular velocity) is correct because the moment of inertia depends on the mass, mass distribution, and axis of rotation, but not on the angular velocity.
131 Medium
131 of 157
Application +4 | -1
If linear density of a rod of length 3m varies as λ=2+x\lambda = 2 + x, then the position of the centre of gravity of the rod is
View answer and explanation
Correct option: C
107m\frac{{10}}{7}m
Option C (107m\frac{{10}}{7}m) is correct because it is the calculated position of the center of gravity using the integral formula for a varying linear density.
132 Medium
132 of 157
Application +4 | -1
A body of mass ‘M’ is moving on a circular track of radius ‘r’ in such a way that its kinetic energy ‘k’ depends on the distance travelled by the body ‘s’ according to relation k=βsk = \beta s, where β\beta is a constant. The angular acceleration of the particle is
View answer and explanation
Correct option: D
βMr\frac{\beta }{{Mr}}
Option D (βMr\frac{\beta}{Mr}) is correct because the angular acceleration is derived from the relationship between kinetic energy, distance traveled, and the radius of the circular track.
133 Medium
133 of 157
Remembering +4 | -1
Position vector of centre of mass of two particles system is given by:
View answer and explanation
Correct option: D
R⃗=m1r⃗1+m2r⃗2m1+m2\vec{R}=\frac{m_1 \vec{r}_1+m_2 \vec{r}_2}{m_1+m_2}
Option D (R⃗=m1r⃗1+m2r⃗2m1+m2\vec{{R}}=\frac{{m_1 \vec{{r}}_1+m_2 \vec{{r}}_2}}{{m_1+m_2}}) is correct because it represents the standard formula for the position vector of the center of mass of a two-particle system.
134 Medium
134 of 157
Application +4 | -1
A thin uniform disc of mass MM and radius RR is rotating in a horizontal plane about an axis passing through its centre and perpendicular to its plane with angular velocity ω\omega. Another disc of same dimension but mass M2\frac{M}{2} is placed gently on the first disc co-axially. The angular velocity of the system now is
View answer and explanation
Correct option: D
2ω3\frac{{2\omega }}{3}
Option D (2ω3\frac{{2\omega }}{{3}}) is correct because the angular momentum is conserved when the second disc is placed on the first, leading to a decrease in angular velocity.
135 Medium
135 of 157
Application +4 | -1
In the equation of angular displacement of a particle moving on a circular path is given as θ=2t3+0.5,θ\theta = 2{t^3} + 0.5,\theta is in radian and t in second. The angular velocity of the particle at t=2s is
View answer and explanation
Correct option: C
24 rad/s
Option C (24 rad/s) is correct because angular velocity is the derivative of angular displacement with respect to time, evaluated at t=2s.
136 Medium
136 of 157
Analyzing +4 | -1
A metre stick is placed vertically at the origin on a frictionless surface. A gentle push in +x+x-direction is given to the top most point of the rod. When it has fallen completely, the xx-coordinate of centre of rod is at
View answer and explanation
Correct option: A
Origin
The correct answer is Origin because there are no external horizontal forces acting on the system, so the center of mass remains at the origin.
137 Medium
137 of 157
Understanding +4 | -1
A uniform disc of mass 2 kg and radius 15 cm is revolving around the central axis by 4 rads−1\mathrm{rad}{\mathrm{s}^{ - 1}}. The linear momentum of disc will be
View answer and explanation
Correct option: D
None of these
Option D (None of these) is correct because the linear momentum of a rotating disc about its center is zero, as the center of mass is at rest.
138 Medium
138 of 157
Analyzing +4 | -1
A large tray of mass M{M} has in it a cubical block of ice of mass m{m} and edge length L{L}. The ice starts melting. The shift in the height of centre of mass of system (ice + tray) is
View answer and explanation
Correct option: C
12mL(m+M)\frac{1}{2} \frac{{mL}}{({m}+{M})}; downward
Option C (12mL(m+M)\frac{1}{2} \frac{{mL}}{({m}+{M})}; downward) is correct because when the ice melts, the center of mass of the ice lowers by L/2, and the overall shift in the center of mass is calculated considering both masses.
139 Medium
139 of 157
Remembering +4 | -1
The correct relation between moment of inertial II, radius of gyration KK and mass MM of the body is:
View answer and explanation
Correct option: D
K=IMK=\sqrt{\frac{I}{M}}
Option D (K=IMK=\sqrt{\frac{{I}}{{M}}}) is correct because the radius of gyration is defined as K=IMK = \sqrt{\frac{{I}}{{M}}}.
140 Medium
140 of 157
Understanding +4 | -1
What is moment of inertia in terms of angular momentum (L) and kinetic energy (K)?
View answer and explanation
Correct option: B
L22K\frac{{{L^2}}}{{2K}}
Option B (L22K\frac{{{L^2}}}{{2K}}) is correct because it correctly relates moment of inertia to angular momentum and kinetic energy.
141 Medium
141 of 157
Analyzing +4 | -1
If α\alpha is angular acceleration, ω\omega is angular velocity and a is the centripetal acceleration then, which of the following is true?
View answer and explanation
Correct option: A
α=ωav\alpha = \frac{{\omega a}}{v}
Option A (α=ωav\alpha = \frac{{\omega a}}{v}) is correct because it relates angular acceleration, angular velocity, centripetal acceleration, and linear velocity correctly.
142 Medium
142 of 157
Analyzing +4 | -1
Statement-1: If a rod is thrown up vertically in absence of air drag, it returns back to the ground without any change in it's angular velocity.
Statement-2: In absence of any torque, the angular momentum of system is conserved.
View answer and explanation
Correct option: A
Statement-1 is true, Statement-2 is true, Statement-2 is the correct explanation for Statement-1
Option A (Statement-1 is true, Statement-2 is true, Statement-2 is the correct explanation for Statement-1) is correct because both statements are true, and Statement-2 explains why Statement-1 is true.
143 Medium
143 of 157
Application +4 | -1
Moment of inertia of big drop in II. If 8 droplets are formed from big drop, then moment of inertia of small droplet is
View answer and explanation
Correct option: A
I32\frac{I}{{32}}
Option A (I32\frac{I}{{32}}) is correct because the moment of inertia of a sphere is proportional to mr2mr^2, and when a big drop splits into 8 smaller drops, the mass of each small drop is m/8m/8 and the radius is r/2r/2.
144 Medium
144 of 157
Remembering +4 | -1
Find the position of centre of mass from the base of a uniform solid cone of height 20 cm20 \mathrm{~cm}.
View answer and explanation
Correct option: A
5 cm5 \mathrm{~cm}
Option A is correct. The center of mass of a uniform solid cone is located at a distance of h/4 from the base, where h is the height of the cone. Therefore, the center of mass is at 20/4 = 5 cm from the base.
145 Medium
145 of 157
Understanding +4 | -1
A car sometimes overturns while taking a turn. When it overturns, it is
View answer and explanation
Correct option: A
The inner wheel which leaves the ground first
Option A is correct because when a car overturns, the inner wheel lifts off the ground first due to the torque and centrifugal force acting on the car.
146 Medium
146 of 157
Understanding +4 | -1
Moment of inertia of a ring of mass M and radius R about an axis passing through the centre and perpendicular to the plane is II. What is the moment of inertia about its diameter
View answer and explanation
Correct option: B
I2\frac{I}{2}
Option B (I2\frac{I}{2}) is correct. The moment of inertia about a diameter is half the moment of inertia about an axis perpendicular to the plane and passing through the center.
147 Medium
147 of 157
Application +4 | -1
A constant torque acting on a uniform circular wheel changes its angular momentum from A0  to  7A0{A_0}\,\,to\,\,\mathrm{ }7{A_0} in 3 s. The magnitude of average torque is
View answer and explanation
Correct option: D
2A02{A_0}
Option D (2A02{A_0}) is correct because the average torque is equal to the rate of change of angular momentum, which is (7A0 - A0)/3 = 2A0.
148 Medium
148 of 157
Remembering +4 | -1
Analogue of mass in rotational motion is
View answer and explanation
Correct option: A
Moment of inertia
Option A (Moment of inertia) is correct because moment of inertia is the measure of an object's resistance to changes in its rotational motion, analogous to mass in linear motion.
149 Medium
149 of 157
Application +4 | -1
A solid sphere of mass 500 g and radius 10 cm rolls without slipping with the velocity 20 cm/s. The total kinetic energy of the sphere will be
View answer and explanation
Correct option: A
0.014  J0.014\;J
Option A (0.014  J0.014\;J) is correct because the total kinetic energy is the sum of translational and rotational kinetic energies for rolling without slipping.
150 Medium
150 of 157
Analyzing +4 | -1
Of the two eggs which have identical sizes, shapes and weights, one is raw, and other is half boiled. The ratio between the moment of inertia of the raw to the half boiled egg bout central axis is
View answer and explanation
Correct option: B
Greater than one
Option B (Greater than one) is correct because the raw egg has its mass distributed further from the center due to the liquid yolk, resulting in a higher moment of inertia.
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