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NEET • PHYSICS • SYSTEM OF PARTICLES

System of particles practice · Mixed difficulty

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Showing 151-180 of 239 questions

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151 Medium
151 of 239
Remembering +4 | -1
What remains constant in the field of central force
View answer and explanation
Correct option: C
Angular momentum
Option C (Angular momentum) is correct because in a central force field, the torque is zero, leading to the conservation of angular momentum.
152 Hard
152 of 239
Application +4 | -1
A uniform metal rod is bent into L shape with the bent arms at 90∘90^\circ to each other. The distance of the centre of mass from the bent point is
View answer and explanation
Correct option: A
142\frac{1}{{4\sqrt 2 }}
Option A (142\frac{1}{{4\sqrt 2 }}) is correct because the center of mass of each arm is at L/2, and then the center of mass of the L shape is calculated considering the symmetry and equal masses.
153 Easy
153 of 239
Application +4 | -1
If all of a sudden the radius of the earth decreases, then
View answer and explanation
Correct option: B
The angular speed of the earth will increase
Option B (The angular speed of the earth will increase) is correct because if the radius decreases, the moment of inertia decreases, and to conserve angular momentum, the angular speed must increase.
154 Medium
154 of 239
Application +4 | -1
The linear acceleration of the centre of gravity of a solid sphere which rolls down without slipping over an inclined plane with an angle of inclination 300{30^0} is
View answer and explanation
Correct option: C
3.5  ms−23.5\,\,m{s^{ - 2}}
Option C (3.5  ms−23.5\,\,m{s^{ - 2}}) is correct because it is the linear acceleration calculated for a solid sphere rolling down an inclined plane without slipping.
155 Medium
155 of 239
Analyzing +4 | -1
STATEMENT-1: If there is no external torque on a body about its center of mass, then the velocity of the center of mass remains constant.

STATEMENT-2: The linear momentum of an isolated system remains constant.
View answer and explanation
Correct option: D
Statement- 1 is False, Statement-2 is True
Option D (Statement- 1 is False, Statement-2 is True) is correct because the velocity of the center of mass remains constant only when there is no external *force*, not torque, and the linear momentum of an isolated system is always conserved.
156 Medium
156 of 239
Application +4 | -1
A particle of mass m is circulating on a circle of radius r having angular momentum L, then the centripetal force will be
View answer and explanation
Correct option: C
L2/mr3{L^2}/m{r^3}
Option C (L2/mr3{L^2}/m{r^3}) is correct because the centripetal force is derived from the angular momentum, mass, and radius of the circular path.
157 Medium
157 of 239
Analyzing +4 | -1
In a bicycle the radius of rear wheel is twice the radius of front wheel. If rF and rr{r_F}\,and\,{r_r} are the radius, vF and vr{v_F}\,and\,{v_r}, are speeds of top most points of wheel, then
View answer and explanation
Correct option: C
vF=vr{v_F} = {v_r}
Option C (vF=vr{v_F} = {v_r}) is correct because the linear speed of both wheels must be the same for the bicycle to move forward.
158 Medium
158 of 239
Application +4 | -1
The radius vector and linear momentum are respectively given by vector 2i^+2j^+k^  and  2i^−2j^+k^\mathrm{2\hat i} + 2\mathrm{\hat j} + \mathrm{\hat k \,\,and\,\, 2\hat i} - 2\mathrm{\hat j} + \mathrm{\hat k}  Their angular momentum is
View answer and explanation
Correct option: B
4i^−8k^4\mathrm{\hat i} - 8\mathrm{\hat k}
Option B (4i^−8k^4\mathrm{\hat i} - 8\mathrm{\hat k}) is correct because the angular momentum is calculated using the cross product of the radius vector and linear momentum: L⃗=r⃗×p⃗\vec{L} = \vec{r} \times \vec{p}.
159 Medium
159 of 239
Understanding +4 | -1
In an elastic head on collision between two particles
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Correct option: A
Velocity of separation is equal to the velocity of approach
Option A (Velocity of separation is equal to the velocity of approach) is correct because this is the defining characteristic of an elastic collision, where kinetic energy is conserved.
160 Medium
160 of 239
Understanding +4 | -1
The centre of mass of a body
View answer and explanation
Correct option: B
May lie within, outside on the surface of the body
Option B (May lie within, outside on the surface of the body) is correct because the center of mass depends on the mass distribution and can be located anywhere relative to the body's physical extent.
161 Medium
161 of 239
Remembering +4 | -1
One circular ring and one circular disc, both are having the same mass and radius. The ratio of their moments of inertia about the axes passing through their centres and perpendicular to their planes, will be
View answer and explanation
Correct option: B
2:12:1
Option B (2:12:1) is correct because the moment of inertia of a ring is MR2MR^2 and that of a disc is 12MR2\frac{1}{2}MR^2, so their ratio is 2:1.
162 Medium
162 of 239
Analyzing +4 | -1
If a force 10i^+15j^+25k^10\hat i + 15\hat j + 25\hat k acts on a system and gives an acceleration 2i^+3j^−5k^2\hat i + 3\hat j - 5\hat k to the centre of mass of the system, the mass of the system is
View answer and explanation
Correct option: D
Given data is not correct
Option D (Given data is not correct) is correct because the force and acceleration vectors are not in the same direction, implying the mass would be a tensor, which is not physically realistic for a simple mass.
163 Easy
163 of 239
Application +4 | -1
The angular displacement of a particle is 5 rad. Then its angular velocity at t=10 sect = 10\,sec is (rads−1)\left( {rad{s^{ - 1}}} \right)
View answer and explanation
Correct option: B
0.5
Option B (0.5) is correct because angular velocity is defined as the angular displacement divided by the time taken, given a constant angular velocity.
164 Medium
164 of 239
Understanding +4 | -1
A small object of mass m is attached to a light string which passes through a hollow tube. The tube is hold by one hand and the string by the other. The object is set into rotation in a circle of radius R and velocity v. The string is then pulled down, shortening the radius of path of rr. What is conserved
View answer and explanation
Correct option: A
Angular momentum
Option A (Angular momentum) is correct because there is no external torque acting on the object, so its angular momentum is conserved.
165 Medium
165 of 239
Application +4 | -1
A body of moment of inertia 4kgm2{4 kgm^2} rotating with an angular speed of 4 rad/s has the 4 x J of kinetic energy. Determine the value of x.
View answer and explanation
Correct option: C
8
Option C (8) is correct because the kinetic energy is calculated as 32 J, and 4 x J equals 32 J, therefore x = 8.
166 Easy
166 of 239
Application +4 | -1
A uniform solid sphere of diameter 0.2 m and mass 10 kg is rotated about its diameter with an angular velocity of 2 rad s−12\,rad\,{s^{ - 1}}. Then its angular momentum in kg m2 s−1kg\,{m^2}\,{s^{ - 1}} is
View answer and explanation
Correct option: C
0.08
Option C (0.08) is correct because it is the angular momentum calculated using the formula L = Iω, where I is the moment of inertia of a solid sphere and ω is the angular velocity.
167 Medium
167 of 239
Understanding +4 | -1
Which of the following statements are incorrect about centre of mass?
I) Centre of mass can coincide with geometrical centre of a body
II) Centre of mass of a system of two particles does not always lie on the line joining the particles
III) Centre of mass should always lie on the body
View answer and explanation
Correct option: A
II and III
Option A (II and III) is correct because the center of mass of two particles always lies on the line joining them, and it doesn't necessarily have to lie on the body itself (e.g., a ring).
168 Medium
168 of 239
Application +4 | -1
A fan is making 600 revolutions per minute. If after some time it makes 1200 revolutions per minute, then increase in its angular velocity is
View answer and explanation
Correct option: B
20  π  rad/sec20\;\pi \;rad/sec
Option B (20  π  rad/sec20\;\pi \;rad/sec) is correct because it is the difference between the final and initial angular velocities after converting revolutions per minute to radians per second.
169 Easy
169 of 239
Application +4 | -1
A constant torque of 500 N-m turns a wheel of moment of inertia 100 kg−m2100\,kg - {m^2} about axis through its centre. Its angular velocity after 6 sec is
View answer and explanation
Correct option: C
30 radsec⁡30\,\frac{{rad}}{{\sec }}
Option C (30 radsec⁡30\,\frac{{rad}}{{\sec }}) is correct because it is the angular velocity calculated using the formula relating torque, moment of inertia, and angular acceleration.
170 Medium
170 of 239
Analyzing +4 | -1
A disk and a sphere of same radius but different masses roll off on two inclined planes of the same altitude and length. Which one of the two objects gets to the bottom of the plane first?
View answer and explanation
Correct option: B
Sphere
Option B (Sphere) is correct because for the same height and length, the sphere has a lower moment of inertia compared to the disk, resulting in a greater linear acceleration and reaching the bottom first.
171 Easy
171 of 239
Application +4 | -1
A thick straight wire of length 4π m 4\pi \,m\, is fixed at its midpoint and the bent in the form of a circle. The shift in its centre of mass is
View answer and explanation
Correct option: C
2 m
Option C (2 m) is correct because when the wire is bent into a circle, the center of mass shifts from the midpoint of the wire to the center of the circle, which is a distance equal to the radius of the circle.
172 Medium
172 of 239
Application +4 | -1
A curved road of diameter 1.8 km is banked so that no friction is required at a speed of 30  ms−130\;\mathrm{m}{\mathrm{s}^{ - 1}}. What is the banking angle?
View answer and explanation
Correct option: A
60{6^0}
Option A (60{6^0}) is correct because it is the correct banking angle calculated using the given speed and radius.
173 Medium
173 of 239
Understanding +4 | -1
A bomb travelling in a parabolic path under gravity, explodes in mid air. The centre of mass of fragments will move
View answer and explanation
Correct option: D
In the parabolic path as the unexploded bomb would have travelled
Option D (In the parabolic path as the unexploded bomb would have travelled) is correct because the center of mass continues to follow the original parabolic trajectory, irrespective of the explosion.
174 Medium
174 of 239
Understanding +4 | -1
There are two identical balls of same material, one being solid and the other being hollow. How will you distinguish them without weighing?
View answer and explanation
Correct option: D
By any one of these methods
Option D (By any one of these methods) is correct because all three methods can distinguish between a solid and hollow ball of the same material without weighing.
175 Medium
175 of 239
Analyzing +4 | -1
The centre of mass of a system cannot change its state of motion, unless there is external force acting on it. Yet the internal force of the brakes can bring a car to rest. Then
View answer and explanation
Correct option: C
The car is stopped by the road
The correct answer is C (The car is stopped by the road) because the external force of friction between the tires and the road is what ultimately brings the car to rest.
176 Medium
176 of 239
Application +4 | -1
A stone is swinging in a horizontal circle 0.8 m in diameter, at 30rev/min. A distant light causes a shadow of the stone to be formed on a nearby wall. What is the amplitude of the motion of the shadow? What is the frequency?
View answer and explanation
Correct option: B
0.4 m, 0.5 Hz
Option B (0.4 m, 0.5 Hz) is correct because the amplitude is half the diameter and the frequency is the revolutions per second.
177 Easy
177 of 239
Application +4 | -1
Two objects of mass 100 g and 400 g posses velocity 5i^ m/s5\hat i\,m/s and 3i^+3j^ m/s3\hat i + 3\hat j\,m/s respectively. The velocity of their centre of mass in m/s is
View answer and explanation
Correct option: C
17i^+12j^5\frac{{17\hat i + 12\hat j}}{5}
Option C (17i^+12j^5\frac{{17\hat i + 12\hat j}}{5}) is correct because the velocity of the center of mass is calculated by vcm=m1v1+m2v2m1+m2v_{cm} = \frac{{m_1v_1 + m_2v_2}}{{m_1 + m_2}}.
178 Medium
178 of 239
Analyzing +4 | -1
A uniform thin rod of mass MM and length LL is standing vertically along the YY-axis on a smooth horizontal surface with its lower end at origin (0,0)(0,0). A slight disturbance at t=0t=0 causes the lower end to slip on smooth surface along the positive X-axis and the rod starts falling. The path followed by the centre of mass of the rod during its fall is a/an.
View answer and explanation
Correct option: D
Circle
Option D (Circle) is correct because the center of mass moves in a circular arc as the rod falls, conserving mechanical energy.
179 Hard
179 of 239
Application +4 | -1
The moment of interia of a rod about its perpendicular bisector is II. When the temperature of the rod is increased by ΔT\Delta T, the increase in the moment of inertia of the rod about same axis is (Here, α\alpha is the coefficient of linear expansion o the rod) :
View answer and explanation
Correct option: B
2αIΔT2 \alpha {I} \Delta {T}
Option B (2αIΔT2 \alpha {I} \Delta {T}) is correct because the increase in moment of inertia is proportional to the original moment of inertia, the coefficient of linear expansion, and the change in temperature.
180 Medium
180 of 239
Understanding +4 | -1
A non-zero external force acts on a systems of particles. The velocity and acceleration of the centre of mass are found to be v0 and a0{v_0}\,and\,{a_0} at an instant t. It is possible that
View answer and explanation
Correct option: B
v0=0,a0≠0{v_0} = 0,{a_0} \ne 0
Option B (v0=0,a0≠0{v_0} = 0,{a_0} \ne 0) is correct because a non-zero external force implies a non-zero acceleration of the center of mass, even if the initial velocity is zero.
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