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NEET • PHYSICS • SEMI CONDUCTOR DEVICES

Semi conductor devices practice · Mixed difficulty

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Showing 31-60 of 108 questions

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31 Easy
31 of 108
Understanding +4 | -1
With the fall in temperature, the electric conductivity of intrinsic semiconductors
View answer and explanation
Correct option: B
Decreases
Option B (Decreases) is correct because as temperature falls, the conductivity of intrinsic semiconductors decreases due to reduced thermal excitation of electrons.
32 Medium
32 of 108
Analyzing +4 | -1
A working transistor with its three legs marked P,QP,Q and RR is tested using a multimeter. No conduction is found between PP and QQ. By connecting the common (negative) terminal of the multimeter to RR and the other (positive) terminal to PP or QQ, some resistance is seen on the multimeter. Which of the following is true for the transistor?
View answer and explanation
Correct option: A
It is an n−p−nn - p - n transistor with RR as base
Option A (It is an n−p−nn - p - n transistor with RR as base) is correct because the multimeter shows conduction when the negative terminal is connected to R and the positive terminal to P or Q, indicating that R is the base of an NPN transistor.
33 Medium
33 of 108
Analyzing +4 | -1
The Boolean equation x=[(A+B‾)⋅(B+C)]⋅B\mathrm{x}=[(\mathrm{A}+\overline{\mathrm{B}}) \cdot(\mathrm{B}+\mathrm{C})] \cdot \mathrm{B} can be simplified to
View answer and explanation
Correct option: C
x=A⋅B\mathrm{x}=\mathrm{A} \cdot \mathrm{B}
Option C, x=A⋅B, is correct because simplifying the Boolean equation using Boolean algebra results in this expression.
34 Medium
34 of 108
Remembering +4 | -1
Bonding in a germanium crystal (semi-conductor) is
View answer and explanation
Correct option: D
Covalent
Option D (Covalent) is correct because germanium, being a semiconductor, forms covalent bonds with its neighboring atoms.
35 Medium
35 of 108
Analyzing +4 | -1
An AND gate can be prepared by repetitive use of
(a) NOT gate         \,\,\,\,\,\,\,\, (b) OR gate         \,\,\,\,\,\,\,\, (c) NAND gate         \,\,\,\,\,\,\,\, (d) NOR gate
View answer and explanation
Correct option: B
Only (a) and (b) are correct
Option A (Only (a) and (b) are correct) is correct because an AND gate can be created using a combination of NOT and OR gates.
36 Medium
36 of 108
Understanding +4 | -1
For which of the following the resistance decreases on increasing the temperature
View answer and explanation
Correct option: C
Germanium
Germanium is correct because it is a semiconductor, and its resistance decreases with increasing temperature due to increased carrier concentration.
37 Medium
37 of 108
Understanding +4 | -1
The value of (1β−1α)\left( {\frac{1}{\beta } - \frac{1}{\alpha }} \right) is equal to :- (α\alpha and β\beta are current gain in CB & CE configuration).
View answer and explanation
Correct option: D
-1
Option D (-1) is correct because the relationship between alpha and beta in transistor configurations leads to this result.
38 Easy
38 of 108
Remembering +4 | -1
Integrated chip (IC) is an electronic device that contains
View answer and explanation
Correct option: D
Transistors, resistors and capacitors
Option D (Transistors, resistors and capacitors) is correct because an integrated circuit (IC) typically contains transistors, resistors, and capacitors fabricated on a single semiconductor chip.
39 Medium
39 of 108
Analyzing +4 | -1
Statement-I: The dominant mechanism for motion of charge carriers in forward and reverse biased silicon P−N\mathrm{P}-\mathrm{N} junction are drift in both forward and reverse bias.

Statement-II: In reverse biasing, no current flow through the junction.
View answer and explanation
Correct option: D
If both statements are incorrect.
Option D is correct because both statements are incorrect. The dominant mechanism is diffusion in forward bias and drift in reverse bias. Also, a small current flows in reverse bias due to minority carriers.
40 Easy
40 of 108
Understanding +4 | -1
If a LED forward biased, then
View answer and explanation
Correct option: A
electrons from the nn - type side cross the p−np-n junction and recombine with holes in the pp - type side
Option A (electrons from the nn - type side cross the p−np-n junction and recombine with holes in the pp - type side) is correct because this is the fundamental process that produces light in an LED.
41 Easy
41 of 108
Application +4 | -1
The electrical conductivity of a semiconductor increases when electromagnetic radiation of wavelength shorter than 6200 A∘,6200 \, \mathop {\text{A}}\limits^ \circ, is incident on it. The band gap in (eV) for the semiconductor is
View answer and explanation
Correct option: B
2
2 is correct because the band gap energy is calculated as E=hcλE = \frac{{hc}}{\lambda}, and substituting the given wavelength yields approximately 2 eV.
42 Medium
42 of 108
Remembering +4 | -1
In CECE mode, the input characteristics of a transistor is the variation of
View answer and explanation
Correct option: A
IB{I_B} against VBE{V_{BE}} at constant VCE{V_{CE}}
Option A (IB{I_B} against VBE{V_{BE}} at constant VCE{V_{CE}}) is correct because the input characteristics of a transistor in CE mode show the relationship between base current (IBI_B) and base-emitter voltage (VBEV_{BE}) at a constant collector-emitter voltage (VCEV_{CE}).
43 Medium
43 of 108
Analyzing +4 | -1
Statement I: If forward current changes by 1.5 mA1.5 \mathrm{~mA} when forward voltage in semiconductor diode is changed from 0.5 V0.5 \mathrm{~V} to 2 V2 \mathrm{~V}, the forward resistance of diode will be 1Ω1 \Omega.

Statement II: The forward resistance is given by Rf=ΔVfΔIfR_f=\frac{\Delta V_f}{\Delta I_f}
View answer and explanation
Correct option: D
Statement I is false; Statement II is true
Option D is correct because Statement I is false (the forward resistance is not 1 Ω{\Omega}) and Statement II is true (the formula for forward resistance is correct).
44 Medium
44 of 108
Application +4 | -1
A p−n  p - n\; photodiode is made of a material with a band gap of 2.0 eV. The minimum frequency of the radiation that can be absorbed by the material is nearly
View answer and explanation
Correct option: B
5×10145 \times {10^{14}} Hz
Option B (5×10145 \times {10^{14}} Hz) is correct because the minimum frequency is calculated using E=hfE = hf, where E is the band gap energy.
45 Medium
45 of 108
Analyzing +4 | -1
Assertion: The resistivity of a semi-conductor increases with temperture.

Reason: the atoms of semi conductor vibrate with large amplitude at higher temperture thereby increasing its resistivity.
View answer and explanation
Correct option: D
Assertion and reason both are false
Option D (Assertion and reason both are false) is correct because the resistivity of a semiconductor decreases with temperature, and the reason provided is not the primary cause.
46 Medium
46 of 108
Understanding +4 | -1
A piece of copper and another of germanium are cooled from room temperature (300 K) to 280 K, the resistance of
View answer and explanation
Correct option: A
Copper decreases and germanium increases
Option A (Copper decreases and germanium increases) is correct because the resistance of copper (a metal) decreases with decreasing temperature, while the resistance of germanium (a semiconductor) increases.
47 Medium
47 of 108
Understanding +4 | -1
In Boolean algebra, Aˉ⋅Bˉ‾\overline {\bar A \cdot \bar B} is equal to
View answer and explanation
Correct option: D
A+BA + B
Option D (A+BA + B) is correct because it follows from De Morgan's theorem in Boolean algebra.
48 Medium
48 of 108
Analyzing +4 | -1
Given below are two statements : one is labelled as Assertion A and the other is labelled as Reason R

Assertion A: Photodiodes are used in forward bias usually for measuring the light intensity.

Reason R: For a p-n junction diode, at applied voltage VV the current in the forward bias is more than the current in the reverse bias for ∣Vz∣>±V≥\left|V_{z}\right|> \pm V \geq ∣V0∣\left|V_{0}\right| where V0V_{0} is the threshold voltage and VzV_{z} is the breakdown voltage.

In the light of the above statements, choose the correct answer from the options given below
View answer and explanation
Correct option: A
A is false but R is true
Option A (A is false but R is true) is correct because photodiodes are used in reverse bias, and the statement about forward and reverse bias current is correct.
49 Medium
49 of 108
Understanding +4 | -1
If De{D_e} , Db{D_b} and Dc{D_c} are the doping levels of emitter, base and collector respectively of a transistor, then
View answer and explanation
Correct option: D
De{D_e} >Dc{D_c} > Db{D_b}
Option D (De{D_e} >Dc{D_c} > Db{D_b}) is correct because the emitter is most heavily doped to supply the majority carriers, the collector is moderately doped to collect these carriers, and the base is lightly doped to minimize recombination.
50 Medium
50 of 108
Remembering +4 | -1
The saturation current in a diode valve is governed by
View answer and explanation
Correct option: C
Richardson’s law
Option C (Richardson’s law) is correct because Richardson's law describes the relationship between the thermionic emission current density and the temperature of the cathode in a vacuum tube.
51 Medium
51 of 108
Understanding +4 | -1
The mobility of free electrons is greater than that of free holes because they
View answer and explanation
Correct option: B
Require low energy to continue their motion
Option B (Require low energy to continue their motion) is correct because free electrons have lower effective mass and require less energy to move through the crystal lattice compared to holes.
52 Medium
52 of 108
Application +4 | -1
Two diodes have resistance 20 Ω\mathrm{\Omega } and is centretapped with rms secondary voltage from centre tap to each end of secondary 50 V. If external resistance is 980 Ω\mathrm{\Omega }. What is mean load?
View answer and explanation
Correct option: B
45 mA
Option B (45 mA) is correct because it is the approximate mean load current calculated using the given diode resistance, external resistance, and secondary voltage.
53 Medium
53 of 108
Remembering +4 | -1
The temperature coefficient of resistance of a conductor is
View answer and explanation
Correct option: A
Positive always
Option A (Positive always) is correct because the resistance of a conductor generally increases with temperature.
54 Medium
54 of 108
Analyzing +4 | -1
Assertion : Photodiode & photovoltaic cell are based on the same principle.

Reason : Both use same method of operations to work.
View answer and explanation
Correct option: C
If Assertions is True but the reason is False
Option C is correct. While both photodiode and photovoltaic cells use semiconductors and p-n junctions, they operate on different principles. Photodiodes are typically reverse biased and detect light, while photovoltaic cells generate voltage from light.
55 Medium
55 of 108
Understanding +4 | -1
Would there be any advantage to adding nn-type or pp-type impurities to copper
View answer and explanation
Correct option: B
No
No, because copper is already a good conductor, and adding impurities would decrease its conductivity.
56 Medium
56 of 108
Remembering +4 | -1
In a P-type semiconductor, the acceptor impurity produces an energy level
View answer and explanation
Correct option: D
Just above the valence band
Option D (Just above the valence band) is correct because acceptor impurities create energy levels slightly above the valence band, allowing electrons to easily jump into them, creating holes.
57 Medium
57 of 108
Application +4 | -1
A common emitter amplifier is designed with NPNNPN transistor (α=0.99)\left( {\alpha = 0.99} \right). The input impedance is 1  KΩ1\;K\mathrm{\Omega } and load is 10  KΩ10\;K\mathrm{\Omega }. The voltage gain will be
View answer and explanation
Correct option: C
990
Option C (990) is correct because the voltage gain of a common emitter amplifier is approximately equal to the product of beta and the ratio of load resistance to input impedance.
58 Medium
58 of 108
Remembering +4 | -1
In Colpitt oscillator the feedback network consists of
View answer and explanation
Correct option: B
Two capacitors and an inductor
Option B (Two capacitors and an inductor) is correct because a Colpitts oscillator uses a feedback network consisting of two capacitors and one inductor to create the necessary phase shift for oscillation.
59 Medium
59 of 108
Understanding +4 | -1
The output of a NAND gate is 0
View answer and explanation
Correct option: C
If both inputs are 1
Option C (If both inputs are 1) is correct because a NAND gate outputs 0 only when both inputs are 1.
60 Medium
60 of 108
Application +4 | -1
A zener diode has a contact potential of 1 V in the absence of biasing. It undergoes Zener breakdown for an electric field of 106{10^6} V-m−1{\mathrm{m}^{ - 1}} at the depletion region of pp-nn junction. If the width of the depletion region is 2.5 μ\mum, what should be the reverse biased potential for the Zener breakdown to occur?
View answer and explanation
Correct option: B
2.5 V
Option A (3.5 V) is correct because the Zener breakdown voltage is the sum of the contact potential and the voltage drop across the depletion region due to the electric field.
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