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NEET • PHYSICS • MOTION IN PLANE

Motion in plane practice · Medium

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Showing 151-176 of 176 questions
151 Medium
151 of 176
Analyzing +4 | -1
If a2+b2+c2=1a^2+b^2+c^2=1 where a,b,c∈Ra, b, c \in R, then the maximum value of (4a−3b)2+(5b−4c)2+(3c−5a)2(4 a-3 b)^2+(5 b-4 c)^2+(3 c-5 a)^2 is
View answer and explanation
Correct option: B
50
Option B (50) is correct because the maximum value of the expression is obtained when the expression is expanded and simplified using the given condition a2+b2+c2=1a^2 + b^2 + c^2 = 1.
152 Medium
152 of 176
Understanding +4 | -1
Two vectors A⃗\vec{A} and B⃗\vec{B} are such that A⃗+B⃗=C⃗\vec{A}+\vec{B}=\vec{C} and A2+B2=C2A^2+B^2=C^2. Which of the following statements is correct?
View answer and explanation
Correct option: A
A⃗\vec{A} is perpendicular to B⃗\vec{B}
Option A (A⃗\vec{A} is perpendicular to B⃗\vec{B}) is correct because the equation A2+B2=C2A^2 + B^2 = C^2 implies that the vectors A⃗\vec{A} and B⃗\vec{B} form a right-angled triangle, meaning they are perpendicular.
153 Medium
153 of 176
Understanding +4 | -1
A: Two row boats moving parallel to each other and nearby, are attracted towards each other
R: Increase of velocity of fluid flow decrease the pressure
View answer and explanation
Correct option: A
Both A and R are true and R is the correct explanation of A
Option A is correct because Bernoulli's principle explains that faster fluid flow results in lower pressure, causing the boats to be drawn together.
154 Medium
154 of 176
Analyzing +4 | -1
The vector i^+xj^+3k^\hat{\mathbf{i}}+\mathrm{x} \hat{\mathbf{j}}+3 \hat{\mathrm{k}} is rotated through an angle θ\theta and doubled in magnitude, then it becomes 4i^+(4x−2)j^+2k^4 \hat{i}+(4 x-2) \hat{j}+2 \hat{k}. The possible positive value of xx is
View answer and explanation
Correct option: D
2
Option D (2) is correct because by equating the magnitudes and using the given transformation, we can solve for x and find the positive value.
155 Medium
155 of 176
Application +4 | -1
A boat takes two hours to travel 8 km and back in still water. If the velocity of water 4 kmh−1\mathrm{km}{\mathrm{h}^{ - 1}}, the time taken for going ups tream 8km and coming back is
View answer and explanation
Correct option: B
2 h 40 min
Option B (2 h 40 min) is correct because the total time is the sum of the upstream and downstream travel times, calculated using relative velocities.
156 Medium
156 of 176
Understanding +4 | -1
A ball is projected with velocity v0{v_0} at an angle of elevation 300{30^0}. Mark the correct statement
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Correct option: C
Horizontal component of momentum will be conserved
Option C (Horizontal component of momentum will be conserved) is correct because in projectile motion, the horizontal component of velocity remains constant (if air resistance is negligible), and thus the horizontal component of momentum is conserved.
157 Medium
157 of 176
Application +4 | -1
Consider a vector F→=4i^−3j^\overrightarrow F = 4\widehat i - 3\widehat j. Another vector that is perpendicular to F→\overrightarrow F is
View answer and explanation
Correct option: C
7k^7\widehat k
Option C (7k^7\widehat k) is correct because the dot product of the two vectors is zero, indicating they are perpendicular.
158 Medium
158 of 176
Application +4 | -1
What is the unit vector along i^+j^  ?\hat i + \hat j\,\,?
View answer and explanation
Correct option: A
i^+j^2\frac{{\hat i + \hat j}}{{\sqrt 2 }}
Option A (i^+j^2\frac{{\hat i + \hat j}}{{\sqrt 2 }}) is correct because a unit vector is found by dividing the vector by its magnitude.
159 Medium
159 of 176
Understanding +4 | -1
IF u→=ai^+bj^+ck^  with i^,j^,k^\overrightarrow u = a\widehat i + b\widehat j + c\widehat k\,\,with\,\hat i,\hat j,\hat k are in east, north and vertical directions, horizontal component of velocity of projectile is
View answer and explanation
Correct option: C
a2+b2\sqrt {{a^2} + {b^2}}
Option C (a2+b2\sqrt {{a^2} + {b^2}}) is correct because the horizontal component of velocity is the vector sum of the eastward and northward components, which can be found using the Pythagorean theorem.
160 Medium
160 of 176
Understanding +4 | -1
Statement-I: If dot product and cross product of a⃗\vec{a} and b⃗\vec{b} are zero, it implies that one of the vector a⃗\vec{a} and b⃗\vec{b} must be a null vector.
Statement-II: Null vector is a vector with zero magnitude.
View answer and explanation
Correct option: A
Statement-I is true and statement-II is true
Statement-I is true because if both the dot product and cross product are zero, at least one of the vectors must be a null vector. Statement-II is true because a null vector is defined as a vector with zero magnitude.
161 Medium
161 of 176
Application +4 | -1
A stone is projected from the ground with velocity 50  ms−150\mathrm{\;m}{\mathrm{s}^{ - 1}} and angle of 300{30^0}. It crosses a wall after 3 s. How far beyond the wall the stone will strike the ground?
View answer and explanation
Correct option: C
86.6 m
Option C (86.6 m) is correct because it involves calculating the total range and subtracting the distance to the wall to find the distance beyond the wall.
162 Medium
162 of 176
Application +4 | -1
Vector A⃗\vec A has magnitude of 5 unit directed along east, then vector 6A⃗6\vec A
View answer and explanation
Correct option: C
Has magnitude 30 unit along East
Option C (Has magnitude 30 unit along East) is correct because multiplying a vector by a scalar multiplies its magnitude by that scalar, while the direction remains the same.
163 Medium
163 of 176
Understanding +4 | -1
Statement-I: Finite angular displacement is not a vector quantity.
Statement-II: It does not obey the laws of vector addition.
View answer and explanation
Correct option: A
Both statements are true
Option C is correct because the mass is calculated using Newton's second law, where force equals mass times acceleration.
164 Medium
164 of 176
Application +4 | -1
The angle between the vectors (i→+j→+k→)(\overrightarrow i + \overrightarrow j + \overrightarrow k ) and (i→−j→−k→)(\overrightarrow i - \overrightarrow j - \overrightarrow k ) is
View answer and explanation
Correct option: A
sin⁡−183{\sin ^{ - 1}}\frac{{\sqrt 8 }}{3}
Option A (sin⁡−183{\sin ^{ - 1}}\frac{{\sqrt 8 }}{3}) is correct because it is the angle calculated using the dot product formula and the relationship between dot product and sine of the angle.
165 Medium
165 of 176
Analyzing +4 | -1
Two boys PP and QQ are playing on a river bank. PP plans to swim across the river directly and come back. QQ plans to swim downstream by a length equal to the width of the river and then come back. Both of them bet each other, claiming that the boy succeeding in less time will win. Assuming the swimming rate of both PP and QQ to the same, it can be concluded that
View answer and explanation
Correct option: A
PP wins
Option A is correct because P wins. The time taken by P is less than the time taken by Q, as the effect of the river's current is more significant for Q's downstream and upstream swim.
166 Medium
166 of 176
Application +4 | -1
A vector A→\overrightarrow A points vertically upward and B→\overrightarrow B points towards north. The vector product of A→ × B→\overrightarrow A \, \times \,\overrightarrow B is
View answer and explanation
Correct option: B
Along west
Option B (Along west) is correct because the cross product follows the right-hand rule, resulting in a vector pointing west.
167 Medium
167 of 176
Analyzing +4 | -1
Assertion : If a body of mass m is projected upwards with a speed V making an angle θ\theta with the vertical, than the change in the momentum of the body along X–axis is zero.
Reason : Mass of the body remains constant along X–axis.
View answer and explanation
Correct option: B
Assertion is correct, reason is correct; reason is not a correct explanation for assertion
Option B (Assertion is correct, reason is correct; reason is not a correct explanation for assertion) is correct because while both statements are true, the constant mass along the x-axis doesn't directly explain why the change in momentum is zero.
168 Medium
168 of 176
Understanding +4 | -1
Two bullets are fired simultaneously, horizontally and with different speeds from the same place. Which bullet will hit the ground first?
View answer and explanation
Correct option: C
Both will hit simultaneously
Option C is correct because the time to hit the ground depends only on the initial height and the vertical acceleration due to gravity, which are the same for both bullets.
169 Medium
169 of 176
Application +4 | -1
If the resultant of two forces (A+B) and (A−D) is A2+B2\left( {A + B} \right)\,and\,\left( {A - D} \right)\,is\,\sqrt {{A^2} + {B^2}} , then the angle between these forces is
View answer and explanation
Correct option: C
cos⁡−1[−A2+B22(A2−B2)]{\cos ^{ - 1}}\left[ { - \frac{{{A^2} + {B^2}}}{{2\left( {{A^2} - {B^2}} \right)}}} \right]
Option C (cos⁡−1[−A2+B22(A2−B2)]{\cos ^{ - 1}}\left[ { - \frac{{{A^2} + {B^2}}}{{2\left( {{A^2} - {B^2}} \right)}}} \right]) is correct because the angle between the forces is found using the law of cosines and simplifying the expression.
170 Medium
170 of 176
Application +4 | -1
The maximum horizontal range of a projectile is 400 m. The maximum value of the height attained by it will be
View answer and explanation
Correct option: A
100 m
Option A (100 m) is correct because the maximum height is related to the maximum range by the formula H = R/4 when the range is maximum.
171 Medium
171 of 176
Analyzing +4 | -1
The time of flight of a projectile on an upward inclined plane depends upon
View answer and explanation
Correct option: D
both 1 and 2
Option D (both 1 and 2) is correct because the time of flight on an inclined plane depends on both the angle of projection and the angle of inclination.
172 Medium
172 of 176
Application +4 | -1
The vector that must be added to the vector i^−3j^+2k^ and 3i^+6j^−7k^\widehat i - 3\widehat j + 2\widehat k\,and\,3\widehat i + 6\widehat j - 7\widehat k so that the resultant vector is a unit vector along the y-axis is
View answer and explanation
Correct option: B
−4i^−2j^+5k^- 4\widehat i - 2\widehat j + 5\widehat k
Option B (−4i^−2j^+5k^- 4\widehat i - 2\widehat j + 5\widehat k) is correct because, when added to the given vectors, it results in a unit vector along the y-axis.
173 Medium
173 of 176
Understanding +4 | -1
What is the angle between (P→+Q→)(\overrightarrow{\mathrm{P}}+\overrightarrow{\mathrm{Q}}) and (P→×Q‾)(\overrightarrow{\mathrm{P}} \times \overline{\mathrm{Q}})
View answer and explanation
Correct option: C
π2\frac{\pi}{2}
Option C (π2\frac{\pi}{2}) is correct because the cross product of two vectors is always perpendicular to the plane containing the two vectors, and the sum of two vectors lies in the same plane.
174 Medium
174 of 176
Remembering +4 | -1
For angle …X…\ldots X \ldots the projectile has maximum range and it is equal to ...X.... Here, X\mathrm{X} and Y\mathrm{Y} refer to
View answer and explanation
Correct option: C
π4\frac{\pi}{4} and v02g\frac{v_0^2}{g}
Option C (π4\frac{\pi}{4} and v02g\frac{v_0^2}{g}) is correct because the maximum range is achieved at an angle of π4\frac{\pi}{4} radians (45 degrees) and the maximum range is v02g\frac{v_0^2}{g}.
175 Medium
175 of 176
Application +4 | -1
Given A⃗=i^+2j^−3k^\mathrm{\vec A} = \hat i + 2\hat j - 3\hat k. When a vector B⃗\mathrm{\vec B} is added to A⃗\mathrm{\vec A}, We get a unit vector along X=axis. Then,B⃗\mathrm{\vec B} is
View answer and explanation
Correct option: A
−2j^+3k^- 2\hat j + 3\hat k
Option A (−2j^+3k^- 2\hat j + 3\hat k) is correct because when added to A⃗\vec{A}, it results in a unit vector along the x-axis.
176 Medium
176 of 176
Analyzing +4 | -1
The plane which can be formed with the vectors a→=3i→−4j→+2k→\overrightarrow a = 3\overrightarrow i - 4\overrightarrow j + 2\overrightarrow k,b→=2i→−j→−6k→,c→=5i→−5j→−4k→\overrightarrow b = 2\overrightarrow i - \overrightarrow j - 6\overrightarrow k ,\overrightarrow c = 5\overrightarrow i - \overrightarrow {5j} - 4\overrightarrow k IS
View answer and explanation
Correct option: B
triangle
Option B (triangle) is correct because the vectors are coplanar and can form a triangle since their sum is zero.
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