Skip to main content
Back to MOTION IN PLANE

Your Progress

0 / 176 Answered
0
Correct
0
Incorrect
0%
Accuracy
NEET • PHYSICS • MOTION IN PLANE

Motion in plane practice · Medium

Choose an answer to check it, or open “View answer” to study the explanation. Sign in to save progress to your account.

Practice format and chapter quiz

The practice player uses single-correct-answer MCQs. Chapter quizzes help you review a topic; they are not full-length NEET mock papers.

Take a chapter quiz →
Showing 91-120 of 176 questions

Preparing practice and saved progress…

91 Medium
91 of 176
Analyzing +4 | -1
The angle between two vectors AA and BB is θ\theta. Vector RR is the resultant of the two vectors. If RR makes an θ2\frac{\theta}{2} with AA, then
View answer and explanation
Correct option: C
A=B\mathrm{A}=\mathrm{B}
Option C (A=B\mathrm{A}=\mathrm{B}) is correct because if the resultant R makes an angle of θ/2\theta/2 with A, then the magnitudes of A and B must be equal.
92 Medium
92 of 176
Application +4 | -1
The kinetic energy of a projectile becomes half of its initial kinetic energy at maximum height. The maximum height of the projectile is (u→u \toinitial velocity)
View answer and explanation
Correct option: B
u24g\frac{{{u^2}}}{{4g}}
Option B (u24g\frac{{{u^2}}}{{4g}}) is correct because the kinetic energy at maximum height is half the initial kinetic energy, allowing us to relate the initial velocity to the maximum height.
93 Medium
93 of 176
Application +4 | -1
The resultant of two vectors of magnitudes 2A and 2A  {\sqrt 2 A\;} acting at an angle θ\theta is 10A\sqrt {10} A. The correct value of θ\theta is
View answer and explanation
Correct option: B
450{45^0}
Option B (450{45^0}) is correct because using the law of cosines, (10A)2=(2A)2+(2A)2+2(2A)(2A)cosθ({\sqrt {10} A})^2 = (2A)^2 + ({\sqrt 2 A})^2 + 2(2A)({\sqrt 2 A})cos\theta, which simplifies to 10A2=4A2+2A2+42A2cosθ10A^2 = 4A^2 + 2A^2 + 4{\sqrt 2 A^2}cos\theta, leading to cosθ=12cos\theta = \frac{1}{{\sqrt 2 }} and θ=450\theta = 45^0.
94 Medium
94 of 176
Understanding +4 | -1
Assertion: A man can cross river of width dd in minimum time. On increasing the river velocity, minimum time to cross the river by man will remain unchanged.
Reason: As velocity of a river is perpendicular to its width so time to cross the river is independent of velocity of river.
View answer and explanation
Correct option: A
If both Assertion & Reason are True & the Reason is a correct explanation of the Assertion
Option A is correct because the minimum time to cross a river depends only on the swimmer's speed and the river's width, not the river's velocity.
95 Medium
95 of 176
Analyzing +4 | -1
If two non-parallel vectors A⃗\vec{A} and B⃗\vec{B} are equal in magnitude, then the vectors (A⃗−B⃗)(\vec{A}-\vec{B}) and (A⃗+B⃗)(\vec{A}+\vec{B}) will be
View answer and explanation
Correct option: C
Perpendicular to each other
Option C (Perpendicular to each other) is correct because the dot product of (A⃗−B⃗)(\vec{A}-\vec{B}) and (A⃗+B⃗)(\vec{A}+\vec{B}) is zero, indicating perpendicularity.
96 Medium
96 of 176
Application +4 | -1
Two vectors are given by a→=−2i^+j^−3k^\overrightarrow a = - 2\widehat i + \widehat j - 3\widehat k and b→=5i^+3j^−2k^\overrightarrow b = 5\widehat i + 3\widehat j - 2\widehat k. If 3a→+2b→−C→=03\overrightarrow a + 2\overrightarrow b - \overrightarrow C = 0 then third vector c→\overrightarrow c is
View answer and explanation
Correct option: A
4i^+9j^−13k^4\widehat i + 9\widehat j - 13\widehat k
Option A (4i^+9j^−13k^4\widehat i + 9\widehat j - 13\widehat k) is correct because it is the result of the vector operation 3a→+2b→3\overrightarrow a + 2\overrightarrow b.
97 Medium
97 of 176
Application +4 | -1
A cannon on a level plane is aimed at an angle θ\theta above the horizontal and a shell is fired with muzzle velocity v0{v_0} towards a cliff D distance away. The height at which the cannon strikes the cliff is given by
View answer and explanation
Correct option: C
Dtan⁡θ−12gD2v02cos⁡2θD\tan \theta - \frac{1}{2}\frac{{g{D^2}}}{{v_0^2{{\cos }^2}\theta }}
Option C (Dtan⁡θ−12gD2v02cos⁡2θD\tan \theta - \frac{1}{2}\frac{{g{D^2}}}{{v_0^2{{\cos }^2}\theta }}) is correct. It combines the equations for horizontal and vertical motion under constant acceleration.
98 Medium
98 of 176
Analyzing +4 | -1
Two forces are such that the sum of their magnitudes is 18N and their resultant is perpendicular to the smaller force and magnitude of the resultant is 12N . Then the magnitudes of the forces are
View answer and explanation
Correct option: B
5N,12N
Option B (5N,12N) is correct because these magnitudes satisfy the conditions where their sum is 18N and the resultant is 12N, perpendicular to the smaller force.
99 Medium
99 of 176
Analyzing +4 | -1
Statement-I: The sum and difference of two vectors will be equal in magnitude, when the two vectors are perpendicular to each other.
Statement-II: If either of the two vectors is a null vector.
View answer and explanation
Correct option: A
Statement-I is true and statement-II is true
Option A is correct because both statements are true. The sum and difference of two perpendicular vectors have equal magnitudes, and a null vector doesn't affect vector addition or subtraction.
100 Medium
100 of 176
Analyzing +4 | -1
The resultant of the two vectors A⃗\vec{A} and B⃗\vec{B} makes angle α\alpha with A⃗\vec{A} and β\beta with B⃗\vec{B}.

Statement (A) : α<β\alpha<\beta if ∣A⃗∣<∣B⃗∣|\vec{A}|<|\vec{B}|

Statement (B) : α<β\alpha<\boldsymbol{\beta} if ∣A→∣>∣B⃗∣|\overrightarrow{{A}}|>|\vec{B}|

Statement (C) : α=β\alpha=\beta if ∣A⃗∣=∣B⃗∣|\vec{A}|=|\vec{B}|
View answer and explanation
Correct option: C
(B) and (C) are true
Option C is correct because statement (B) and (C) are true. The resultant is closer to the vector with larger magnitude, and when magnitudes are equal, the angles are equal.
101 Medium
101 of 176
Analyzing +4 | -1
Assertion : When the range of projectile is maximum, the time of flight is the largest.
Reason : Range is maximum when angle of projection is 45∘45^\circ
View answer and explanation
Correct option: D
Assertion is incorrect, reason is correct.
Option D is correct because the assertion is false, as maximum time of flight occurs at 90 degrees, while the reason is true, stating the range is maximum at 45 degrees.
102 Medium
102 of 176
Remembering +4 | -1
Velocity is
View answer and explanation
Correct option: B
vector
Option B (vector) is correct because velocity has both magnitude and direction.
103 Medium
103 of 176
Application +4 | -1
What is the angle between i^+j^+k^ and i^\hat i + \hat j + \hat k\,and\,\hat i
View answer and explanation
Correct option: D
None of these
Option D (None of these) is correct because the angle between the vectors is approximately 54.7 degrees, which is not listed in the options.
104 Medium
104 of 176
Analyzing +4 | -1
If a×b=b×c≠0\mathbf{a} \times \mathbf{b}=\mathbf{b} \times \mathbf{c} \neq 0, then the correct statement is
View answer and explanation
Correct option: C
(a+c)∥b(a+c) \| b
Option C ((a+c)∥ba+c) \| b) is correct because the given condition a×b=b×c\mathbf{a} \times \mathbf{b}=\mathbf{b} \times \mathbf{c} implies that b\mathbf{b} is parallel to (a+c)(\mathbf{a} + \mathbf{c}).
105 Medium
105 of 176
Understanding +4 | -1
In the entire path of a projectile, the quantity that remains unchanged is
View answer and explanation
Correct option: B
Horizontal component of velocity
Option B (Horizontal component of velocity) is correct because in projectile motion, the horizontal component of velocity remains constant due to the absence of horizontal acceleration.
106 Medium
106 of 176
Understanding +4 | -1
Three vectors a⃗,b⃗\vec{a}, \vec{b} and c⃗\vec{c} satisfy the relation a⃗⋅b⃗=0\vec{a} \cdot \vec{b}=0 and a⃗⋅c⃗=0\vec{a} \cdot \vec{c}=0. The vector a⃗\vec{a} is parallel to
View answer and explanation
Correct option: D
b⃗×c⃗\vec{b} \times \vec{c}
Option D is correct because if a⃗⋅b⃗=0\vec{a} \cdot \vec{b}=0 and a⃗⋅c⃗=0\vec{a} \cdot \vec{c}=0, then a⃗\vec{a} is perpendicular to both b⃗\vec{b} and c⃗\vec{c}, meaning it's parallel to their cross product.
107 Medium
107 of 176
Application +4 | -1
Two forces of magnitude F have a resultant of the same magnitude F. The angle between the two forces is
View answer and explanation
Correct option: B
120∘120^\circ
Option B (120∘120^\circ) is correct because when two forces of equal magnitude F have a resultant of the same magnitude F, the angle between them is 120 degrees.
108 Medium
108 of 176
Analyzing +4 | -1
Assertion : Two balls of different masses are thrown vertically upward with same speed. They will pass through their point of projection in the downward direction with the same speed.
Reason : The maximum height and downward velocity attained at the point of projection are independent of the mass of the ball.
View answer and explanation
Correct option: B
Assertion is correct, reason is correct; reason is not a correct explanation for assertion
Option B is correct. Both the assertion and reason are correct, but the reason is not the correct explanation for the assertion. The assertion is true due to conservation of energy, and the reason correctly states that maximum height and downward velocity are independent of mass.
109 Medium
109 of 176
Remembering +4 | -1
The horizontal range of a projectile is maximum when the angle of projection is
View answer and explanation
Correct option: C
450{45^0}
Option C (450{45^0}) is correct because the horizontal range of a projectile is maximum when the angle of projection is 45 degrees.
110 Medium
110 of 176
Understanding +4 | -1
The angle between A⃗   and B⃗ is θ\mathrm{\vec A}\;\,and\,\mathrm{\vec B}\,is\,\theta, the value of the triple product A⃗.B⃗×A⃗\mathrm{\vec A}\mathrm{.\vec B} \times \mathrm{\vec A} is
View answer and explanation
Correct option: B
Zero
Option B (Zero) is correct because the triple product of a vector with the cross product of itself and another vector is always zero.
111 Medium
111 of 176
Analyzing +4 | -1
Statement-I: If the magnitude of the sum of two unit vectors is a unit vector, then magnitude of their difference is 3\sqrt{3}
Statement-II: ∣a⃗∣+∣b⃗∣=∣a⃗+b⃗∣|\vec{a}|+|\vec{b}|=|\vec{a}+\vec{b}|
View answer and explanation
Correct option: B
Statement-I is true and statement-II is false
Statement-I is true because the magnitude of the difference of two unit vectors whose sum has unit magnitude is indeed 3\sqrt{3}. Statement-II is false because it only holds when the vectors are in the same direction.
112 Medium
112 of 176
Understanding +4 | -1
Assertion: The magnitude of the resultant of two vectors P⃗\vec{P} and Q⃗\vec{Q} is maximum (P+Q)(P+Q), when the two vectors act in the same direction and minimum (P−Q)(P-Q), when they act in opposite directions.

Reason: The resultant of two vectors can be found by using the relation

R=P2+Q2+2PQcos⁡θR=\sqrt{P^2+Q^2+2 P Q \cos \theta}
View answer and explanation
Correct option: B
If both assertion and reason are true but reason is not
correct explanation of the assertion.
Option B (If both assertion and reason are true but reason is not correct explanation of the assertion) is correct because both the assertion about maximum and minimum resultant magnitudes and the reason stating the formula for resultant magnitude are true, but the formula doesn't directly explain the assertion.
113 Medium
113 of 176
Application +4 | -1
A boat can travel at a speed of 8 kmph in still water on a lake. In the flowing water of a stream, it can move at 8kmph relative to the water in the stream. If the stream speed is 3kmph, how fast can the boat move past a tree on the shore in travelling (i) upstream (ii) downstream?
View answer and explanation
Correct option: A
5 kmph and 11 kmph
Option A (5 kmph and 11 kmph) is correct because it accurately calculates the boat's speed relative to the shore both upstream and downstream by considering the stream's effect.
114 Medium
114 of 176
Understanding +4 | -1
Assertion: The time taken by a boat to cover a certain distance upstream is more than the time taken to cover the same distance downstream.

Reason: The speed of the boat is lesser while moving upstream as compared to downstream due to the speed of the stream.
View answer and explanation
Correct option: A
Both Assertion and Reason are true, and Reason is the correct explanation for Assertion
Option A is correct because the effective speed is lower upstream and higher downstream, leading to longer travel time upstream.
115 Medium
115 of 176
Analyzing +4 | -1
Of the vectors given below, the parallel vectors are,

A⃗=6i^+8j^B⃗=210i^+280k^C⃗=5.1i^+6.8j^D⃗=3.6i^+6j^+48k^\begin{aligned} & \vec{A}=6 \hat{i}+8 \hat{j} \\ & \vec{B}=210 \hat{i}+280 \hat{k} \\ & \vec{C}=5.1 \hat{i}+6.8 \hat{j} \\ & \vec{D}=3.6 \hat{i}+6 \hat{j}+48 \hat{k} \end{aligned}
View answer and explanation
Correct option: B
A→\overrightarrow{\mathrm{A}} and C→\overrightarrow{\mathrm{C}}
Option B (A→\overrightarrow{\mathrm{A}} and C→\overrightarrow{\mathrm{C}}) is correct because parallel vectors have proportional components, and the ratio of the components of A and C are equal.
116 Medium
116 of 176
Application +4 | -1
GivenP⃗.Q⃗=0 then ∣P⃗×Q⃗∣ is\mathrm{\vec P}\mathrm{.\vec Q} = 0\,then\,\left| {\mathrm{\vec P} \times \mathrm{\vec Q}} \right|\,is
View answer and explanation
Correct option: A
∣P⃗∣∣Q⃗∣\left| {\mathrm{\vec P}} \right|\left| {\mathrm{\vec Q}} \right|
Option A (∣P⃗∣∣Q⃗∣\left| \mathrm{\vec P} \right|\left| \mathrm{\vec Q} \right|) is correct because if the dot product of two vectors is zero, they are perpendicular, and the magnitude of their cross product is the product of their magnitudes.
117 Medium
117 of 176
Application +4 | -1
The resultant of two vector of equal magnitude is twice of magnitude of either of the vectors the angle between them is
View answer and explanation
Correct option: C
00{0^0}
Option C (00{0^0}) is correct because if the resultant of two vectors of equal magnitude is twice the magnitude of either vector, the vectors must be in the same direction, hence the angle is 0 degrees.
118 Medium
118 of 176
Application +4 | -1
The adjacent sides of a parallelogram are represented by co-initial vectors 2i^+3j^ and i^+4j^2\hat i + 3\hat j\,and\,\hat i + 4\hat j. The area of the parallelogram is
View answer and explanation
Correct option: A
5 units along z- axis
Option A (5 units along z- axis) is correct because the area of the parallelogram is the magnitude of the cross product of the vectors, which results in a vector along the z-axis.
119 Medium
119 of 176
Application +4 | -1
If the vector A⃗=2i^+4j^  and  B⃗=5i^+pj^\mathrm{\vec A} = 2\hat i + 4\hat j\,\,and\,\,\mathrm{\vec B} = 5\hat i + \mathrm{p\hat j} are parallel to each other, the magnitude of B⃗\mathrm{\vec B} is
View answer and explanation
Correct option: A
555\sqrt 5
Option A (555\sqrt 5) is correct because parallel vectors have proportional components, allowing us to determine 'p' and then the magnitude of B.
120 Medium
120 of 176
Application +4 | -1
If A→=2i^+3j^+4k^  and  B⃗=4i^+3j^+2k^\overrightarrow A = 2\hat i + 3\hat j + 4\hat k\,\,and\,\,\mathrm{\vec B} = 4\hat i + 3\hat j + 2\hat k, then angle between A→\overrightarrow A and B⃗\mathrm{\vec B} is
View answer and explanation
Correct option: C
cos⁡−1(25/29){\cos ^{ - 1}}\left( {25/29} \right)
Option C (cos⁡−1(25/29){\cos ^{ - 1}}\left( {25/29} \right)) is correct because it is the angle between the two vectors calculated using the dot product formula.
Revision notes and key takeaways

Review MOTION IN PLANE in your textbook or class notes, then use this set to check your understanding.

Showing 91-120 of 176 questions

Your practice

0 / 176 answered · 176 remaining · 0% accuracy

Progress is stored on this device. Sign in to save to your account.

✓ Correct · ✗ Incorrect · ○ Unanswered

Answer feedback and difficulty

Type at least 2 characters or jump directly:
🔓

Save your learning progress

Sign in with a free account to save your practice answers and quiz results, then return to them when you revise.