Skip to main content
Back to MOTION IN PLANE

Your Progress

0 / 303 Answered
0
Correct
0
Incorrect
0%
Accuracy
NEET • PHYSICS • MOTION IN PLANE

Motion in plane practice · Mixed difficulty

Choose an answer to check it, or open “View answer” to study the explanation. Sign in to save progress to your account.

Practice format and chapter quiz

The practice player uses single-correct-answer MCQs. Chapter quizzes help you review a topic; they are not full-length NEET mock papers.

Take a chapter quiz →
Showing 61-90 of 303 questions

Preparing practice and saved progress…

61 Easy
61 of 303
Understanding +4 | -1
The unit vectors along the three co-ordinate axes are related as
View answer and explanation
Correct option: D
i^=j^=k^=1\hat{\mathrm{i}}=\hat{\mathrm{j}}=\hat{\mathrm{k}}=1
Option D (i^=j^=k^=1\hat{\mathrm{i}}=\hat{\mathrm{j}}=\hat{\mathrm{k}}=1) is correct because unit vectors along coordinate axes have a magnitude of 1.
62 Hard
62 of 303
Analyzing +4 | -1
Statement I Two forces (P+Q) and (P-Q) where P⊥QP \bot Q, when act at an angle θ1{\theta _1} to each other, the magnitude of their resultant is 3(P2+Q2),\sqrt {3({P^2} + {Q^2})} , when they act at an angle θ2,{\theta _2}, the magnitude of their resultant becomes 2(P2+Q2)\sqrt {2({P^2} + {Q^2})}. This is possible only when θ1<θ2.{\theta _1} < {\theta _2}.
Statement II In the situation given above. θ1=60∘  and  θ2=90∘{\theta _1} = {60^ \circ }\,\,\mathrm{and}\,\,{\theta _2} = {90^ \circ }
In the light of the above statements, choose the most appropriate answer from the options given below.
View answer and explanation
Correct option: B
Both Statement I and Statement II are true
Option B (Both Statement I and Statement II are true) is correct because both statements accurately describe the resultant of two forces P+Q and P-Q under given conditions.
63 Medium
63 of 303
Application +4 | -1
(P⃗+Q⃗)\left( {\mathrm{\vec P} + \mathrm{\vec Q}} \right) is a unit vector along X-axis. If P⃗=i^−j^+k^,\mathrm{\vec P} = \hat i - \hat j + \hat k, then what value is Q⃗?\mathrm{\vec Q}?
View answer and explanation
Correct option: B
j^−k^\hat j - \hat k
Option D (j^−k^\hat j - \hat k) is correct because the sum of P⃗\vec P and Q⃗\vec Q must result in a unit vector along the x-axis, which is i^\hat i.
64 Medium
64 of 303
Analyzing +4 | -1
The magnitudes of a set of 3 vectors are given below. The set of vectors for which the resultant cannot be zero is
View answer and explanation
Correct option: D
10,20,4010,20,40
Option D (10, 20, 40) is correct because the sum of the two smaller magnitudes (10+20=30) is less than the largest magnitude (40), so they cannot form a closed triangle and the resultant cannot be zero.
65 Medium
65 of 303
Understanding +4 | -1
A bomb is dropped from an aeroplane moving horizontally at constant speed. When air resistance is taken into consideration, the bomb
View answer and explanation
Correct option: B
Fall to earth behind the aeroplane
Option B is correct. Due to air resistance, the bomb loses horizontal velocity and falls behind the aeroplane.
66 Medium
66 of 303
Understanding +4 | -1
Consider the following statements and select the correct statements from the following.
I. Addition and subtraction of scalars make sense only for quantities with same units
II. Multiplication and division of scalars with different units is possible
III. Addition, subtraction, multiplication and division of scalars with same unit is possible
View answer and explanation
Correct option: D
I, II and III
Option D (I, II and III) is correct because all three statements regarding scalar operations and units are valid.
67 Hard
67 of 303
Application +4 | -1
A ship AA sailing due east with a velocity of 10km/h10 km / h happens to appear sailing due north with a velocity of 5km/h5 km / h, to a person, sitting in a moving ship B.B. Determine the velocity (absolute) of ship B.B.
View answer and explanation
Correct option: A
55km/h,tan⁡−1(1/2)S5 \sqrt{5} km / h , \tan ^{-1}(1 / 2) S of E
Option A (55km/h,tan⁡−1(1/2)S5 \sqrt{5} km / h , \tan ^{-1}(1 / 2) S of E) is correct because it accurately calculates the absolute velocity of ship B by considering the relative velocity and the velocity of ship A.
68 Medium
68 of 303
Analyzing +4 | -1
Assertion : A shell fired from a gun is moving along the parabolic path. If it explodes at the top of the trajectory, then no part of the shell can fly vertically.
Reason : The vertical momentum of the shell at the top of the trajectory is zero.
View answer and explanation
Correct option: D
Assertion is incorrect, reason is correct.
Option D is correct because the assertion is false; even if the vertical momentum is zero at the top, fragments can have vertical components after the explosion. The reason is correct; the vertical momentum of the shell is zero at the top.
69 Medium
69 of 303
Application +4 | -1
A mosquito is moving with a velocity V = (0.5 t2i^ + 3 tj^ + 9k^) m/sV\, = \,(0.5\,{t^2}\hat i\, + \,3\,t\hat j\, + \,9\hat k)\,m/s and accelerating in uniform conditions. What will be the directions of mosquito after 2s?
View answer and explanation
Correct option: B
tan−1(409)from  x−axis\mathrm{ta}{\mathrm{n}^{\mathrm{ - 1}}}\left( {\frac{{\sqrt {40} }}{9}} \right)\mathrm{from}{\mkern 1mu} {\mkern 1mu} x - \mathrm{axis}
Option B (tan−1(409)from  x−axis\mathrm{ta}{\mathrm{n}^{\mathrm{ - 1}}}\left( {\frac{{\sqrt {40} }}{9}} \right)\mathrm{from}{\mkern 1mu} {\mkern 1mu} x - \mathrm{axis}) is correct because it is the angle the velocity vector makes with the x-axis after 2 seconds.
70 Hard
70 of 303
Application +4 | -1
If a+b+c=0\mathbf{a}+\mathbf{b}+\mathbf{c}=0, then a×b\mathbf{a} \times \mathbf{b} is equal to
View answer and explanation
Correct option: A
b×c\mathbf{b} \times \mathbf{c}
Option A (b×c\mathbf{b} \times \mathbf{c}) is correct because if a+b+c=0\mathbf{a} + \mathbf{b} + \mathbf{c} = 0, then a=−(b+c)\mathbf{a} = -(\mathbf{b} + \mathbf{c}), and a×b=−(b+c)×b=−(b×b+c×b)=−c×b=b×c\mathbf{a} \times \mathbf{b} = -(\mathbf{b} + \mathbf{c}) \times \mathbf{b} = -(\mathbf{b} \times \mathbf{b} + \mathbf{c} \times \mathbf{b}) = -\mathbf{c} \times \mathbf{b} = \mathbf{b} \times \mathbf{c}.
71 Medium
71 of 303
Analyzing +4 | -1
The ranges and heights for two projectiles projected with the same initial velocity at angles 42o  and 48o{42^\mathrm{o}}\,\,\mathrm{and }\,\mathrm{4}{\mathrm{8}^\mathrm{o}} with the horizontal are R1,R2  and H1,H2,{R_1},{R_2}\mathrm{ }\,\,\mathrm{and }\,{H_1},{H_2}, respectively. Choose the correct option.
View answer and explanation
Correct option: B
R1=R2  and  H1<H2{R_1} = {R_2}\mathrm{ }\,\,\mathrm{and }\,\,{H_1} < {H_2}
Option B is correct because ranges are equal for complementary angles, and height is greater for the larger angle.
72 Easy
72 of 303
Analyzing +4 | -1
Assertion: Three projectiles are moving in different paths in the air. Vertical component of relative velocity between any of the pair does not change with time as long as they are in air. (Neglecting the effect of air friction)
Reason: Relative acceleration between any of the pair of projection is zero.
View answer and explanation
Correct option: A
If both Assertion and Reason are true and Reason is the correct explanation of Assertion
Option A (If both Assertion and Reason are true and Reason is the correct explanation of Assertion) is correct because the relative acceleration between the projectiles is zero, leading to a constant vertical component of relative velocity.
73 Easy
73 of 303
Understanding +4 | -1
Out of the following quantities, which is scalar?
View answer and explanation
Correct option: C
Potential energy
Option C (Potential energy) is correct because potential energy is a scalar quantity, having only magnitude.
74 Easy
74 of 303
Understanding +4 | -1
Assertion At highest point of a projectile, dot product of velocity and acceleration is zero.

Reason At highest point, velocity and acceleration are mutually perpendicular.
View answer and explanation
Correct option: A
If both Assertion and Reason are correct and Reason is the correct explanation of Assertion.
Option A is correct because at the highest point, the velocity is horizontal, and the acceleration is vertical (due to gravity), making them perpendicular, hence their dot product is zero.
75 Medium
75 of 303
Understanding +4 | -1
If the angle between two forces increases, the magnitude of their resultant
View answer and explanation
Correct option: A
Decreases
Option A (Decreases) is correct because as the angle between two forces increases, the cosine of the angle decreases, leading to a smaller resultant magnitude.
76 Hard
76 of 303
Application +4 | -1
The sum of two unit vectors is also a vector of unit magnitude, then the magnitude of the difference of the two unit vectors is
View answer and explanation
Correct option: C
3\sqrt 3 units
Option C (3\sqrt 3 units) is correct because the magnitude of the difference of two unit vectors, when their sum is also a unit vector, is 3\sqrt 3.
77 Hard
77 of 303
Application +4 | -1
A projectile is fired with a velocity v at right angle to the slope which is inclined at an angle θ\theta with the horizontal. What is the time of flight?
View answer and explanation
Correct option: A
2v2gtan⁡θ\frac{{2{v^2}}}{\mathrm{g}}\tan \mathrm{\theta }
Option A (2v2gtan⁡θ\frac{{2{v^2}}}{\mathrm{g}}\tan \mathrm{\theta }) is correct. The time of flight is calculated by considering the component of gravity along the inclined plane.
78 Medium
78 of 303
Understanding +4 | -1
At the point of a projectile motion, acceleration and velocity are perpendicular to each other?
View answer and explanation
Correct option: C
At the top most point
Option C (At the top most point) is correct because at the highest point of the trajectory, the vertical component of velocity is zero, and the acceleration due to gravity is perpendicular to the horizontal velocity.
79 Medium
79 of 303
Analyzing +4 | -1
Given that A⃗+B⃗+C⃗=0\mathrm{\vec A} + \mathrm{\vec B} + \mathrm{\vec C} = 0. Out of three vectors, two are equal in magnitude and the magnitude of third vector is&nbsp;2\sqrt 2 times that of either of the two having equal magnitude. Then the angles between vectors are given by
View answer and explanation
Correct option: B
90∘,135∘,135∘90^\circ ,135^\circ ,135^\circ
Option B (90∘,135∘,135∘90^\circ ,135^\circ ,135^\circ) is correct because it satisfies the condition that the sum of the three vectors is zero, with two vectors equal in magnitude and the third being 2\sqrt{2} times the magnitude of the others.
80 Medium
80 of 303
Understanding +4 | -1
Given θ\theta is the angle between A⃗ and B⃗\mathrm{\vec A}\,and\,\mathrm{\vec B}. Then ∣A^×B^  ∣\left| {\hat A \times \hat B\;} \right| is equal to
View answer and explanation
Correct option: A
sin⁡θ\sin \theta
Option A (sin⁡θ\sin \theta) is correct because the magnitude of the cross product of two unit vectors is the sine of the angle between them.
81 Medium
81 of 303
Analyzing +4 | -1
A river flows with a speed more than the maximum speed with which a person can swim in still water. He intends to cross the river by the shortest possible path (i.e., he wants to reach the point on the opposite bank which directly opposite to the starting point). Which of the following is correct?
View answer and explanation
Correct option: D
The man cannot cross the river in that way.
Option D is correct because if the river's speed is greater than the swimmer's speed, he cannot reach the point directly opposite his starting point.
82 Medium
82 of 303
Understanding +4 | -1
Given c⃗=a⃗×b⃗\mathrm{\vec c} = \mathrm{\vec a} \times \mathrm{\vec b}. The angle which a⃗\mathrm{\vec a} makes with c⃗\mathrm{\vec c} is
View answer and explanation
Correct option: C
900{90^0}
Given c⃗=a⃗×b⃗\mathrm{\vec c} = \mathrm{\vec a} \times \mathrm{\vec b}, the angle which a⃗\mathrm{\vec a} makes with c⃗\mathrm{\vec c} is 900{90^0} because the cross product results in a vector perpendicular to both original vectors.
83 Easy
83 of 303
Application +4 | -1
If A⃗=i^+j^+k^\vec A = \hat i + \hat j + \hat k and B⃗=2i^−j^+4k^\vec B = 2\hat i - \hat j + 4\hat k then the unit vector along A⃗+B⃗\vec A + \vec B is
View answer and explanation
Correct option: C
3i^+5k^34\frac{{3\hat i + 5\hat k}}{{\sqrt {34} }}
Option C (3i^+5k^34\frac{{3\hat i + 5\hat k}}{{\sqrt {34} }}) is correct because it's the unit vector in the direction of the sum of the two vectors.
84 Medium
84 of 303
Analyzing +4 | -1
Statement-I: If a⃗\vec{a} is perpendicular to b⃗\vec{b} and c→\overrightarrow{{c}}, then a→×(b→×c→)=0\overrightarrow{{a}} \times(\overrightarrow{{b}} \times \overrightarrow{{c}})=0
Statement-II: If b→\overrightarrow{{b}} is perpendicular to c→\overrightarrow{{c}}, then b→×c→=0\overrightarrow{{b}} \times \overrightarrow{{c}}=0
View answer and explanation
Correct option: B
Statement-I is true and statement-II is false
Option B (Statement-I is true and statement-II is false) is correct because the vector triple product simplifies to zero under the given conditions, while the cross product of perpendicular vectors is non-zero.
85 Easy
85 of 303
Analyzing +4 | -1
Assertion: If ∣A⃗+B⃗∣=∣A⃗−B⃗∣|\vec{A}+\vec{B}|=| \vec{A}-\vec{B} \mid, then the angle between A⃗\vec{A} and B⃗\vec{B} is 90∘90^{\circ}.
Reason: A⃗+B⃗=B⃗+A⃗\vec{A}+\vec{B}=\vec{B}+\vec{A}
View answer and explanation
Correct option: B
If both Assertion and Reason are true, but Reason is not the correct explanation of Assertion
Option B (If both Assertion and Reason are true, but Reason is not the correct explanation of Assertion) is correct because both statements are true, but the reason doesn't explain the assertion.
86 Easy
86 of 303
Application +4 | -1
A force 2i^+j^−k^2\hat i + \hat j - \hat k newton acts on a body which is initially at rest. If the velocity of the body at the end of 20 seconds is 4i^+2j^+2k^  ms−14\hat i + 2\hat j + 2\hat k\,\,m{s^{ - 1}}, the mass of the body.
View answer and explanation
Correct option: C
10 kg
Option C (10 kg) is correct because it's calculated using Newton's second law, relating force, mass, and acceleration.
87 Easy
87 of 303
Application +4 | -1
The angle between the diagonal of a cube with edges of unit length is
View answer and explanation
Correct option: B
cos⁡−1(13){\cos ^{ - 1}}\left( {\frac{1}{3}} \right)
Option B (cos⁡−1(13)\cos ^{ - 1}\left( {\frac{1}{3}} \right)) is correct because it's the angle between the diagonal of a cube and one of its edges.
88 Easy
88 of 303
Understanding +4 | -1
Two bullets are fired horizontally with different velocities from the same height. Which will reach the ground first?
View answer and explanation
Correct option: C
Both will reach simultaneously
Option C is correct because the time to reach the ground depends only on the height and the vertical component of the initial velocity, which is zero in both cases.
89 Medium
89 of 303
Application +4 | -1
For a particle projected with speed of 20 m/s from ground, the kinetic energy at top most point of trajectory is (14)th\left( {\frac{1}{4}} \right)th of the initial kinetic energy. The angle of projection from horizontal is
View answer and explanation
Correct option: B
60∘60^\circ
Option B (60∘60^\circ) is correct. The angle of projection is determined by the ratio of kinetic energies at the initial point and the top of the trajectory.
90 Easy
90 of 303
Application +4 | -1
The unit vector parallel to the resultant of vectors A→=4i^+3j^+6k^\overrightarrow A = 4\hat i + 3\hat j + 6\hat k and B→=−i^+3j^−8k^\overrightarrow B = - \hat i + 3\hat j - 8\hat k is
View answer and explanation
Correct option: A
17(3i^+6j^−2k^)\frac{1}{7}\left( {3\hat i + 6\hat j - 2\hat k} \right)
Option A (17(3i^+6j^−2k^)\frac{1}{7}\left( {3\hat i + 6\hat j - 2\hat k} \right)) is correct because it's the unit vector in the direction of the resultant vector.
Revision notes and key takeaways

Review MOTION IN PLANE in your textbook or class notes, then use this set to check your understanding.

Showing 61-90 of 303 questions

Your practice

0 / 303 answered · 303 remaining · 0% accuracy

Progress is stored on this device. Sign in to save to your account.

✓ Correct · ✗ Incorrect · ○ Unanswered

Answer feedback and difficulty

Type at least 2 characters or jump directly:
🔓

Save your learning progress

Sign in with a free account to save your practice answers and quiz results, then return to them when you revise.