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NEET • PHYSICS • MOTION IN PLANE

Motion in plane practice · Mixed difficulty

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Showing 271-300 of 303 questions

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271 Medium
271 of 303
Application +4 | -1
What is the unit vector along i^+j^  ?\hat i + \hat j\,\,?
View answer and explanation
Correct option: A
i^+j^2\frac{{\hat i + \hat j}}{{\sqrt 2 }}
Option A (i^+j^2\frac{{\hat i + \hat j}}{{\sqrt 2 }}) is correct because a unit vector is found by dividing the vector by its magnitude.
272 Easy
272 of 303
Understanding +4 | -1
I. Displacing a vector parallel to itself leaves the vector unchanged.

II. Three equal vectors cannot add upto zero.

Which of the following statement(s) is/are correct?
View answer and explanation
Correct option: A
Only I
Option A is correct. Displacing a vector parallel to itself doesn't change it, but three equal vectors can add up to zero if they are oriented at 120 degrees to each other.
273 Medium
273 of 303
Understanding +4 | -1
IF u→=ai^+bj^+ck^  with i^,j^,k^\overrightarrow u = a\widehat i + b\widehat j + c\widehat k\,\,with\,\hat i,\hat j,\hat k are in east, north and vertical directions, horizontal component of velocity of projectile is
View answer and explanation
Correct option: C
a2+b2\sqrt {{a^2} + {b^2}}
Option C (a2+b2\sqrt {{a^2} + {b^2}}) is correct because the horizontal component of velocity is the vector sum of the eastward and northward components, which can be found using the Pythagorean theorem.
274 Easy
274 of 303
Application +4 | -1
If two vectors A‾=2i→−2j→+k→\overline A = 2\overrightarrow i - 2\overrightarrow j + \overrightarrow k, and B‾=2i→+6j→−mk→\overline B = 2\overrightarrow i + 6\overrightarrow j - m\overrightarrow k are perpendicular to each other than the value of mm is
View answer and explanation
Correct option: C
-8
If two vectors A‾=2i→−2j→+k→\overline A = 2\overrightarrow i - 2\overrightarrow j + \overrightarrow k and B‾=2i→+6j→−mk→\overline B = 2\overrightarrow i + 6\overrightarrow j - m\overrightarrow k are perpendicular to each other, then the value of mm is -8 because their dot product must be zero.
275 Medium
275 of 303
Understanding +4 | -1
Statement-I: If dot product and cross product of a⃗\vec{a} and b⃗\vec{b} are zero, it implies that one of the vector a⃗\vec{a} and b⃗\vec{b} must be a null vector.
Statement-II: Null vector is a vector with zero magnitude.
View answer and explanation
Correct option: A
Statement-I is true and statement-II is true
Statement-I is true because if both the dot product and cross product are zero, at least one of the vectors must be a null vector. Statement-II is true because a null vector is defined as a vector with zero magnitude.
276 Medium
276 of 303
Application +4 | -1
A stone is projected from the ground with velocity 50  ms−150\mathrm{\;m}{\mathrm{s}^{ - 1}} and angle of 300{30^0}. It crosses a wall after 3 s. How far beyond the wall the stone will strike the ground?
View answer and explanation
Correct option: C
86.6 m
Option C (86.6 m) is correct because it involves calculating the total range and subtracting the distance to the wall to find the distance beyond the wall.
277 Medium
277 of 303
Application +4 | -1
Vector A⃗\vec A has magnitude of 5 unit directed along east, then vector 6A⃗6\vec A
View answer and explanation
Correct option: C
Has magnitude 30 unit along East
Option C (Has magnitude 30 unit along East) is correct because multiplying a vector by a scalar multiplies its magnitude by that scalar, while the direction remains the same.
278 Medium
278 of 303
Understanding +4 | -1
Statement-I: Finite angular displacement is not a vector quantity.
Statement-II: It does not obey the laws of vector addition.
View answer and explanation
Correct option: A
Both statements are true
Option C is correct because the mass is calculated using Newton's second law, where force equals mass times acceleration.
279 Medium
279 of 303
Application +4 | -1
The angle between the vectors (i→+j→+k→)(\overrightarrow i + \overrightarrow j + \overrightarrow k ) and (i→−j→−k→)(\overrightarrow i - \overrightarrow j - \overrightarrow k ) is
View answer and explanation
Correct option: A
sin⁡−183{\sin ^{ - 1}}\frac{{\sqrt 8 }}{3}
Option A (sin⁡−183{\sin ^{ - 1}}\frac{{\sqrt 8 }}{3}) is correct because it is the angle calculated using the dot product formula and the relationship between dot product and sine of the angle.
280 Medium
280 of 303
Analyzing +4 | -1
Two boys PP and QQ are playing on a river bank. PP plans to swim across the river directly and come back. QQ plans to swim downstream by a length equal to the width of the river and then come back. Both of them bet each other, claiming that the boy succeeding in less time will win. Assuming the swimming rate of both PP and QQ to the same, it can be concluded that
View answer and explanation
Correct option: A
PP wins
Option A is correct because P wins. The time taken by P is less than the time taken by Q, as the effect of the river's current is more significant for Q's downstream and upstream swim.
281 Easy
281 of 303
Application +4 | -1
The position vector rˉ\bar r of a particle is given by rˉ=(Asin⁡ωt)i+(Acos⁡ωt)j\bar r = \left( {A\sin \omega t} \right)i + \left( {A\cos \omega t} \right)j. If vv is velocity of particle. Then vˉ. rˉ=\bar v.\,\bar r =
View answer and explanation
Correct option: A
Zero
The horizontal component of a force is given by Fcos⁡θF \cos \theta. Knowing the horizontal component and the angle, we can find the magnitude of the force. Then, the vertical component is Fsin⁡θF \sin \theta, which gives us 87 N, making option C correct.
282 Medium
282 of 303
Application +4 | -1
A vector A→\overrightarrow A points vertically upward and B→\overrightarrow B points towards north. The vector product of A→ × B→\overrightarrow A \, \times \,\overrightarrow B is
View answer and explanation
Correct option: B
Along west
Option B (Along west) is correct because the cross product follows the right-hand rule, resulting in a vector pointing west.
283 Easy
283 of 303
Understanding +4 | -1
When a projectile is fired at an angle θ\theta wrt. horizontal with velocity uu, then its vertical component
View answer and explanation
Correct option: C
goes on decreasing with height.
Option C (goes on decreasing with height) is correct because the vertical component of velocity decreases due to the effect of gravity as the projectile rises.
284 Hard
284 of 303
Understanding +4 | -1
A vector a\mathbf{a} is turned without a change in its length through a small angles dθd \theta. The value of ∣Δa∣|\Delta \mathbf{a}| and Δa\Delta a are, respectively.
View answer and explanation
Correct option: B
a⋅dθ,0a \cdot d \theta, 0
Option B (a⋅dθ,0a \cdot d \theta, 0) is correct because the magnitude of the change in the vector is adθa d\theta and the change in the magnitude of the vector is 0 since the length remains constant.
285 Medium
285 of 303
Analyzing +4 | -1
Assertion : If a body of mass m is projected upwards with a speed V making an angle θ\theta with the vertical, than the change in the momentum of the body along X–axis is zero.
Reason : Mass of the body remains constant along X–axis.
View answer and explanation
Correct option: B
Assertion is correct, reason is correct; reason is not a correct explanation for assertion
Option B (Assertion is correct, reason is correct; reason is not a correct explanation for assertion) is correct because while both statements are true, the constant mass along the x-axis doesn't directly explain why the change in momentum is zero.
286 Easy
286 of 303
Application +4 | -1
If two directional cosine of a vectors are 12\frac{1}{{\sqrt 2 }} and 13\frac{1}{{\sqrt 3 }} then the value of third directional cosine is
View answer and explanation
Correct option: A
16\frac{1}{{\sqrt 6 }}
Option A (16\frac{1}{{\sqrt 6 }}) is correct because the sum of the squares of the directional cosines must equal 1.
287 Medium
287 of 303
Understanding +4 | -1
Two bullets are fired simultaneously, horizontally and with different speeds from the same place. Which bullet will hit the ground first?
View answer and explanation
Correct option: C
Both will hit simultaneously
Option C is correct because the time to hit the ground depends only on the initial height and the vertical acceleration due to gravity, which are the same for both bullets.
288 Easy
288 of 303
Application +4 | -1
Two forces of 12 N and 8 N act upon a body. The resultant forces on the body has maximum value of
View answer and explanation
Correct option: C
20 N
Option C (20 N) is correct because the maximum resultant force occurs when the two forces act in the same direction, and their magnitudes add up.
289 Easy
289 of 303
Application +4 | -1
The two forces are in the ratio of 2:5 maximum and minimum of their resultant are in the ratio of
View answer and explanation
Correct option: C
0.29375
Option C (0.29375) is correct because it represents the ratio of the maximum and minimum resultant forces calculated from the given ratio of the two forces.
290 Medium
290 of 303
Application +4 | -1
If the resultant of two forces (A+B) and (A−D) is A2+B2\left( {A + B} \right)\,and\,\left( {A - D} \right)\,is\,\sqrt {{A^2} + {B^2}} , then the angle between these forces is
View answer and explanation
Correct option: C
cos⁡−1[−A2+B22(A2−B2)]{\cos ^{ - 1}}\left[ { - \frac{{{A^2} + {B^2}}}{{2\left( {{A^2} - {B^2}} \right)}}} \right]
Option C (cos⁡−1[−A2+B22(A2−B2)]{\cos ^{ - 1}}\left[ { - \frac{{{A^2} + {B^2}}}{{2\left( {{A^2} - {B^2}} \right)}}} \right]) is correct because the angle between the forces is found using the law of cosines and simplifying the expression.
291 Hard
291 of 303
Application +4 | -1
If the equation of motion of a projectile is y=3x−18x2y = 3x - \frac{1}{8}{x^2} the range and maximum height are respectively (yy and xx are in metres)
View answer and explanation
Correct option: B
24m  and  18m24m\,\,\mathrm{and}\,\,18m
Option B (24m  and  18m24m\,\,\mathrm{and}\,\,18m) is correct because it is obtained by comparing the given equation with the standard trajectory equation of a projectile.
292 Easy
292 of 303
Understanding +4 | -1
Which of the following not a vector quantity?
View answer and explanation
Correct option: D
Potential energy
Option D is correct because potential energy is a scalar quantity, while weight, nuclear spin, and momentum are vector quantities.
293 Medium
293 of 303
Application +4 | -1
The maximum horizontal range of a projectile is 400 m. The maximum value of the height attained by it will be
View answer and explanation
Correct option: A
100 m
Option A (100 m) is correct because the maximum height is related to the maximum range by the formula H = R/4 when the range is maximum.
294 Easy
294 of 303
Remembering +4 | -1
Which of the following is vector quantity?
View answer and explanation
Correct option: D
Impulse
Impulse is a vector quantity because it has both magnitude and direction. The other options are scalar quantities.
295 Hard
295 of 303
Application +4 | -1
A boat travels 4 hr upstream and 2 hr down the stream for covering the same distance. The ratio of velocity of boat to the water in river
View answer and explanation
Correct option: B
3:13:1
Option B is correct because the ratio of boat velocity to water velocity is 3:1, derived from equating upstream and downstream distances.
296 Medium
296 of 303
Analyzing +4 | -1
The time of flight of a projectile on an upward inclined plane depends upon
View answer and explanation
Correct option: D
both 1 and 2
Option D (both 1 and 2) is correct because the time of flight on an inclined plane depends on both the angle of projection and the angle of inclination.
297 Medium
297 of 303
Application +4 | -1
The vector that must be added to the vector i^−3j^+2k^ and 3i^+6j^−7k^\widehat i - 3\widehat j + 2\widehat k\,and\,3\widehat i + 6\widehat j - 7\widehat k so that the resultant vector is a unit vector along the y-axis is
View answer and explanation
Correct option: B
−4i^−2j^+5k^- 4\widehat i - 2\widehat j + 5\widehat k
Option B (−4i^−2j^+5k^- 4\widehat i - 2\widehat j + 5\widehat k) is correct because, when added to the given vectors, it results in a unit vector along the y-axis.
298 Medium
298 of 303
Understanding +4 | -1
What is the angle between (P→+Q→)(\overrightarrow{\mathrm{P}}+\overrightarrow{\mathrm{Q}}) and (P→×Q‾)(\overrightarrow{\mathrm{P}} \times \overline{\mathrm{Q}})
View answer and explanation
Correct option: C
π2\frac{\pi}{2}
Option C (π2\frac{\pi}{2}) is correct because the cross product of two vectors is always perpendicular to the plane containing the two vectors, and the sum of two vectors lies in the same plane.
299 Hard
299 of 303
Application +4 | -1
If A⃗=3i^+4j^, B⃗=7i^+24j^\vec A = 3\hat i + 4\hat j,\,\vec B = 7\hat i + 24\hat j then the vector having the same magnitude as B⃗\vec B and parallel to A⃗\vec A is
View answer and explanation
Correct option: B
15i^+20j^15\hat i + 20\hat j
Option B (15i^+20j^15\hat i + 20\hat j) is correct because it has the same magnitude as B⃗\vec B and is parallel to A⃗\vec A.
300 Hard
300 of 303
Application +4 | -1
If a=i^+j^+k^,b=i^+j^,c=i^\mathbf{a}=\hat{\mathbf{i}}+\hat{\mathbf{j}}+\hat{\mathbf{k}}, \mathbf{b}=\hat{\mathbf{i}}+\hat{\mathbf{j}}, \mathbf{c}=\hat{\mathbf{i}} and (a×b)×c=λa+μb(\mathbf{a} \times \mathbf{b}) \times \mathbf{c}=\lambda \mathbf{a}+\mu \mathrm{b}, then λ+μ\lambda+\mu is equal to
View answer and explanation
Correct option: A
0
Option A (0) is correct because after calculating the triple product and comparing it to the given equation, we find that λ + μ = 0.
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